<span>As x approaches positive infinity, f(x) approaches negative infinity, since the graph goes down</span>
Let's begin by listing out the information given to us:
We start out by observing that Triangles MKR & ACD are similar or proportional

We will solve for the missing side by using the similar triangle theorem. This is shown below:~
Answer:
y = 4 sin( 0.5t -
) - 2
y = a sin ( 2t -
) + 2
Step-by-step explanation:
In the first question,
amplitude = 4
Period = 
phase shift = 
Vertical shift = -2
Angular velocity , w = 
Here, w =
= 0.5
The general equation of a wave is
y = a sin( wt + ∅ )
Putting above values in the equation,
y = 4 sin( 0.5t -
) - 2
In the second question,
Amplitude is not given so we will take it as a.
time period = 
w = 2
Phase shift = 
Vertical shift = 2
The equation is
y = a sin ( 2t -
) + 2