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3 years ago

Whats the inequality c−12>−4

Mathematics

1 answer:

marshall27 [118]3 years ago

8 0

Answer:

c>16

Step-by-step explanation:

c-12>4

c> 4+12

c> 16

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What is 20% of 800?

Sedaia [141]

Answer:

160

Step-by-step explanation:

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3 years ago

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N=1500(2^018t), t≥0 Find the initial number of cells (N) in the culture, given the exponential function.

adelina 88 [10]

Answer:

1500

Step-by-step explanation:

Step 1: Understand what the question is asking you

It wants to know how much cells do you start off with or in other words how much cells are in the culture when time is 0

Step 2: Set t = 0

$N = 1500(2^{0.18(0)} )$

Step 3: Solve for N

$N = 1500(2^{0.18(0)} )$

$N = 1500(2^{0} )$

$N = 1500(1 )$

$N = 1500$

Therefore when the initial amount of cells there in the culture is 1500

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4 years ago

Find the 8th term of 27,36,48

Sonbull [250]

Step-by-step explanation:

the sequence is a geometric sequence

simply use the formula:

t(n) = a * (r)^n-1

where n = 8, a = 27, r = 4/3

4 0

4 years ago

Use a 30degrees and -60degrees right triangle to find the exact value of the following trigonometric expression. Cot 30 degrees=

LuckyWell [14K]

The dirty little secret about trig is students mostly just need to understand the 45/45/90 right isosceles triangle and the 30/60/90 triangle, which is half an isosceles triangle.

I'm sure you have seen it many times already, so I'll remind you in the 30/60/90 right triangle the sides opposite those angles are respectively in the ratio $1: \sqrt{3}:2$ . Remember the smallest side is always opposite the smallest angle, etc. These make a right triangle because

$1^2 + \sqrt{3}^2 = 2^2$

So in this hypotenuse 2 triangle, the length 1 side is opposite the 30 degree angle and the $\sqrt{3}$ side is adjacent to it.

We could jump right to the answer but let's enumerate all the trig functions. Really you should memorize the sine and cosine so you can get these quickly.

$\cos 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{hypotenuse} } = \dfrac{\sqrt{3}}{2}$

$\sin 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{hypotenuse} } = \dfrac{1}{2}$

$\tan 30^\circ = \dfrac{ \textrm{opposite} }{ \textrm{adjacent} }= \dfrac{1}{\sqrt{3}} =\dfrac{\sqrt{3}}{3}$

$\cot 30^\circ = \dfrac{ \textrm{adjacent} }{ \textrm{opposite}} = \dfrac{\sqrt{3}}{1} =\sqrt{3}$

$\sec 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{adjacent}}= \dfrac{2}{\sqrt{3}}$

$\csc 30^\circ = \dfrac{ \textrm{hypotenuse} }{ \textrm{opposite}}= \dfrac{2}{1} = 2$

We want the cotangent, another way to get it is

$\cot 30^\circ = \dfrac{\cos 30^\circ}{\sin 30^\circ} = \dfrac{\sqrt{3}/2}{1/2} = \sqrt{3}$

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3 years ago

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For each question below, determine the sale price, given the original price and discount percent

a_sh-v [17]

Answer:

$49

Step-by-step explanation:

$70 - 30% = $49

4 0

3 years ago