(x+3)/2x+5 + (3x-5)/(3x+5)
LCM = ( 2x+5)( 3x+5)
[( x+3)( 3x+5) + ( 3x -5)( 2x+5)]/( 2x+5)( 3x+5)
= (3x^2 + 5x +9 x +15 + 6x^2 + 15x -10x -25)/( 2x+5)( 3x+5)
=( 9 x^2 + 19x -10)/( 2x +5)(3x+5)
A) option
Answer:
x = 2
Step-by-step explanation:
Both equations are equal to y, so they're also equal to each other. We then set them equal to each other:
x^2 - 2x + 1 = x^2 + 2x - 7
We now do algebra to isolate x. Subtract 1 from both sides.
x^2 - 2x = x^2 + 2x - 8
Subtract 2x from both sides.
x^2 - 4x = x^2 - 8
Subtract x^2 from both sides.
-4x = -8
Divide both sides by -4.
x = 2
Answer: C. 4
Step-by-step explanation:
First, we can prime factorize 52.
52 = 2^2 * 13
13 is not a square number, but 4 is a square number because it equals 2 squared.
Therefore, the correct answer is C. 4
