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inysia [295]
3 years ago
15

Plot the image of Point Q under the translation (x,y) (x-3, y + 4)

Mathematics
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

(0, 3)

Step-by-step explanation:

Subtract 3 units from the X-coordinate

Add 4 units from the Y-coordinate

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Verify the identity:<br> tan(x+pi/2)=-cotx<br><br> please!!
olya-2409 [2.1K]
First we use sin(a+b)= sinacosb+sinbcosa
and cos(a+b)=cosa cosb -sinasinb

tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)
and sin(x+pi/2) = sinxcospi/2 + sinpi/2cosx =cosx, 
<span>cos(x+pi/2) = cosxcospi/2- sinxsinpi/2= - sinx, 
</span> because <span>cospi/2 =0,  </span>and <span>sinpi/2=1

</span><span>=tan(x+pi/2)= sin(x+pi/2) / cos(x+pi/2)= cosx / -sinx = -1/tanx = -cotx
</span>from where <span>tan(x+pi/2)=-cotx</span> 
5 0
3 years ago
Find the measure indicated. Assume that the lines which appear to be tangent are tangent. PART 3
ludmilkaskok [199]

I'll do problems 13 and 14 to get you started.

=====================================================

Problem 13

<h3>Answer:  32 degrees</h3>

-----------------------

Explanation:

Refer to the diagram below for problem 13. Since BD is a tangent of the circle, this means angle ABD is 90 degrees, and furthermore x+y = 90. This solves to y = 90-x.

If we focus on triangle ABC, then we can add the interior angles and set the sum equal to 180

A+B+C = 180

z+y+y = 180

z+2y = 180

z+2(90-x) = 180 .... plug in y = 90-x

z+180-2x = 180

z-2x = 180-180

z-2x = 0

z = 2x

We'll use this later.

Now move onto triangle ABD. This is a right triangle due to angle ABD being 90 degrees. The acute angles z and 26 are complementary, meaning they add to 90. So,

z+26 = 90

z = 90-26

z = 64

Now plug this into z = 2x and solve for x

z = 2x

64 = 2x

2x = 64

x = 64/2

x = 32

=====================================================

Problem 14

<h3>Answer: 31 degrees</h3>

-----------------------

Explanation:

Refer to the image shown below for problem 14. Like before, I've added various labels to it to help find the angle we're after (the red angle x).

Note how I've drawn a dashed line from point A to point D. This splits up quadrilateral ABCD into two triangles ABD and ACD. These triangles can be shown to be congruent using the HL (hypotenuse leg) theorem.

The congruent triangles also implies that angle DBC and angle BCD are the same measure (both are shown in green as the variable y).

Focus on triangle BCD. It has interior angles of: y, y and 62. Add them up, set the sum equal to 180.

y+y+62 = 180

2y+62 = 180

2y = 180-62

2y = 118

y = 118/2

y = 59

As the image attachment mentions, the angles x and y add to 90 degrees. This is because angle ABD is 90 degrees, due to segment BD being tangent to the circle. So x+y = 90 leads to x = 90-y, and therefore,

x = 90-y

x = 90-59

x = 31

Side note: it is not a coincidence that we ended up with half of the value of 62.

3 0
3 years ago
Determine the smallest integer value of x in 5x + 3 ≥ 10
Ivanshal [37]

5x + 3 ≥ 10

3 is adding on the left, then it will subtract on the right

5x ≥ 10 -3

5x ≥ 7

5 is multiplying on the left, then it will divide on the right

x ≥ 7/5

x ≥ 1.4

Then, the smallest integer value of x is 2

6 0
1 year ago
Geometry question for homework.
mars1129 [50]

So remember that the distance formula is \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} .

1.

\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3

Distance between (4,-5) and (4,-2) is 3 units.

2.

\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0
3 years ago
*****50 POINTSSSS*****
defon

Answer:

<h3>Given</h3>
  • m∠REG = 78°
  • mAR = 46°
  • ER ≅ GA
<h3>Solution</h3>
  • m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
  • m∠TAR = 1/2mAR = 1/2(46°) = 23°   (tangent chord angle is half the size of intercepted arc)
  • m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
  • mAG = 2m∠GAN = 2(55°) = 110°
  • mRE = mAG = 110° (as ER ≅ GA)
  • mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)
6 0
3 years ago
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