The square has a 44-inch diagonal.
The pythagorean equation must be used to obtain the hand.
Diagonal (d) ^ 2 = side^2 + side ^ 2
Diagonal (d) ^ 2 = 2side (s)^2
d^2 = 2s^2
44^2 = 2s^2
1936 = 2s^2
2s^2 = 1936
s^2 = 968
s = 31.11 inches
The length of the side is around 31 inches
Perimeter = 4*s
Perimeter = 4 * 31
Perimeter = 124 inches
As a result, you will need a total of 124 inches to frame the rectangle.
Hope this helps you!!
Answer:
<abd is 90
<abc is 44
this isnt that hard im in middle school and doing this
Step-by-step explanation:
The length of a rectangle:
L = 2 W + 5
The perimeter:
P = 2 L + 2 W
130 = 2 · ( 2 W + 5 ) + 2 W
130 = 4 W + 10 + 2 W
130 - 10 = 6 W
120 = 6 W
W = 120 : 6
W = 20 in
L = 2 · 20 + 5
L = 40 + 5
L = 45 in.
Finally the area:
A = L · W
A = 20 · 45
A = 900 in²
Answer:
Step-by-step explanation:
(-3)(2)= -6
(l^2w^3)(lw^4) = l^3w^7
-6l^3w^7
