Answer:
This is the balanced equation:
Pb(NO₃)₂ (aq) + 2NaI (aq) → 2NaNO₃ (aq) + PbI₂ (s) ↓
Explanation:
This are the reactants:
PbNO₃
NaI
Iodide can react to Pb²⁺ to make a solid compound.
Oh ah oh ah cheer up baby
Answer:
C.
Explanation:
The electronic configuration of N (7 electrons): 1s² 2s² 2p³.
The orbital 1s is filled with two electrons and their spinning direction is opposite and also electrons of 2s.
3p contains (3 electrons) should fill the 3 orbitals firstly. Every orbital contains 1 electron and be in the same spin direction.
So, the right choice is c.
A is wrong because 2 electrons of 3p are paired in the first orbital before filling every orbital.
B is wrong because the 2 electrons of 1s and 2s are in the same direction and also 2 electrons of 3p are paired in the first orbital before filling every orbital.
D is also wrong the 2 electrons of 1s and 2s are in the same direction and the electron in the second orbital of 3p are in opposite direction of the other 2 electrons.
Answer:
Explanation:
<u>Given Data:</u>
Initial Volume = 
= 7.0 L
Initial Temperature = 
= 300 °C + 273 = 573 K
Final Temperature = = 25.0 °C + 273 = 298 K
<u>Required:</u>
Final Volume = 
= ?
<u>Formula:</u>
<u>[Charles Law] </u>
<u>Solution:</u>
Put the givens
![\displaystyle \frac{7}{573 } =\frac{V_2}{298} \\\\0.01 = \frac{V_2}{298} \\\\\times 298 \ to \ both \ sides\\\\0.01 \times 298 = V_2\\\\3.64 \ L =V_2\\\\\boxed{V_2 =3.64 \ L}\\\\\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B7%7D%7B573%20%7D%20%3D%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C0.01%20%3D%20%5Cfrac%7BV_2%7D%7B298%7D%20%5C%5C%5C%5C%5Ctimes%20298%20%5C%20to%20%5C%20both%20%5C%20sides%5C%5C%5C%5C0.01%20%5Ctimes%20298%20%3D%20V_2%5C%5C%5C%5C3.64%20%5C%20L%20%3DV_2%5C%5C%5C%5C%5Cboxed%7BV_2%20%3D3.64%20%5C%20L%7D%5C%5C%5C%5C%5Crule%5B225%5D%7B225%7D%7B2%7D)
