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Zolol [24]
3 years ago
14

A coffee cup calorimeter will not be used to

Chemistry
2 answers:
drek231 [11]3 years ago
8 0

Answer:

Ingles porfavor

Explanation:

Alekssandra [29.7K]3 years ago
6 0

im rly confused r u j giving out answers

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In which of the following sets is the symbol of the element, the number of protons, and the number of electrons given correctly?
sveta [45]

Answer:

A.

Explanation:

The number of the them will result in A.

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2 years ago
La precipitación ácida es un agente de?
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acid precipitation is an agent of

Explanation:

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3 years ago
PLZ HEL I WILL GIVE BRAINLIEST
NemiM [27]

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3 years ago
Read 2 more answers
the concentration of the radio active isotope potassium-40 in a rock sample is found to be 6.25%. what is the age of the rock
julsineya [31]

Answer:

5.0 x 10⁹ years.

Explanation:

  • It is known that the decay of a radioactive isotope isotope obeys first order kinetics.
  • Half-life time is the time needed for the reactants to be in its half concentration.
  • If reactant has initial concentration [A₀], after half-life time its concentration will be ([A₀]/2).
  • Also, it is clear that in first order decay the half-life time is independent of the initial concentration.
  • The half-life of K-40 = 1.251 × 10⁹ years.

  • For, first order reactions:

<em>k = ln(2)/(t1/2) = 0.693/(t1/2).</em>

Where, k is the rate constant of the reaction.

t1/2 is the half-life of the reaction.

∴ k =0.693/(t1/2) = 0.693/(1.251 × 10⁹ years) = 5.54 x 10⁻¹⁰ year⁻¹.

  • Also, we have the integral law of first order reaction:

<em>kt = ln([A₀]/[A]),</em>

where, k is the rate constant of the reaction (k = 5.54 x 10⁻¹⁰ year⁻¹).

t is the time of the reaction (t = ??? year).

[A₀] is the initial concentration of (K-40) ([A₀] = 100%).

[A] is the remaining concentration of (K-40) ([A] = 6.25%).

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = ln((100%)/( 6.25%))

∴ (5.54 x 10⁻¹⁰ year⁻¹)(t) = 2.77.

∴ t = 2.77/(5.54 x 10⁻¹⁰ year⁻¹) = 5.0 x 10⁹ years.

8 0
3 years ago
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Roundup, an herbicide manufactured by Monsanto, has the formula C₃H₈NO₅P. How many moles of molecules are there in a 304.3-g sam
jekas [21]
<span>The molar mass is 169.09

304.3g/169.09g = 1.799mol which rounds to 1.800 mol</span>
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