Answer:
0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Step-by-step explanation:
In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

In which
x is the number of sucesses
e = 2.71828 is the Euler number
is the mean in the given interval.
Over a long period of time, an average of 14 particles per minute occurs. Assume the arrival of particles at the counter follows a Poisson distribution. Find the probability that at least one particle arrives in a particular one second period.
Each minute has 60 seconds, so 
Either no particle arrives, or at least one does. The sum of the probabilities of these events is decimal 1. So

We want
. So
In which


0.2081 = 20.81% probability that at least one particle arrives in a particular one second period.
Answer:
Step-by-step explanation:
Using soh cah toa
Sin=opp/hot
Sin 52°=h/121
h=sin52°×121
h=0.7880×121feet
h=95.348feet
The sector of the circle formed by its two radius of length 12 inches has an area of 24 pi. This is obtained using the formula, Area is equal to the product of pi, radius squared and central angle all over 360.
Answer:
<h3>55 secs</h3>
Step-by-step explanation:
Given the elevation h (in feet) of the balloon modeled by the function h(x)=−6x+330, we can calculate the time it takes the balloon to reach the ground. The hot air balloon hits the ground at h(x) = 0.
Substitute h(x) = 0 into the modeled expression and find x as shown;
h(x)=−6x+330
0 = −6x+330
6x = 330
Divide both sides by 6
6x/6 = 330/6
x = 55 seconds
Hence the hot air balloon hits the ground after 55 seconds