Answer: He should have ensured the following before beginning work;
1) All circuits must be de-energized before beginning work
2) All controls must be deactivated during work. LOTO(Log out tag out) must be practiced irrespective of the experience of the electrian or worker.
3) Technicians and Electrical workers must be instructed to know the unsafe conditions associated with their work.
Explanation:
We cannot assume that because he is experienced he cannot be prone to all this wrong practices. Humans tend to think that with experience people become less prone to errors and study has shown that this is not true. Safety must be a priority.
Answer:
"150000 N/m²" is the right approach.
Explanation:
According to the question, the pressure on the two spheres 1 and 2 is same.
Sphere 1 and 2:
Then,
⇒ 
⇒ 
and the bulk modulus be,
⇒ 
Sphere 3:
⇒ 
then,
⇒ 
⇒ 
⇒ 
⇒ 
Answer:
D.All of the above
Explanation:
Properties of hydrogen:
1.It is lighter than air.It has density about 0.089 g/L.
2.Hydrogen rapidly change from liquid state to gas,so special protection is required to protect it.
3.It is highly flammable gas.
4.Liquid form of hydrogen exits at -432 F .This is very low temperature so special protection requires to keep it in liquid form.
This refers to the mechanical properties of the materials tested by means of a stress stimulus or deformation. The mechanical behavior of a material will depend on its viscosity / elasticity characteristics. Depending on the response to mechanical stimulus, the material may be classified as elastic or viscous. For a perfectly elastic or Hookian solid the deformation is proportional to the applied stress. A viscous material obeys Newton's law, which states that stress and shear rate are related through an intrinsic characteristic that is viscosity.
However, there are materials that correspond to both properties. Polymers have an intermediate mechanical behavior to elastic and viscous, being called viscoelastic. The elastic and viscous contribution to the mechanical behavior of the polymer depends on the temperature and time scale of the experiment.
Answer:
The open circuit voltage gain is 
Explanation:
Given data is input resistance of an amplifier is
Ω and output resistance of an amplifier is
Ω.
Trans conductance of an amplifier is 
Thus Open circuit voltage gain is

×
×100×
Since 1m=
and 1k=
Thus,

