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1. Band saw lower wheel does not require a guard * true or false 2. Band saw upper guide should be adjusted to within 1/8" of the work piece * true or false 3. Find board & linear ft for 10 pieces of 4" x 4" x 8' *
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Answer for the question:
In , the industries with the most complaints to the Better Business Bureau were banks, cable and satellite television companies, collection agencies, cellular phone providers, and new car dealerships (USA Today, April 16, 2012). The results for a sample of complaints are contained in the DATAfile named BBB. Click on the datafile logo to reference the data."
is explained in the attachment.
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Supply, demand, global markets, imports and exports, and government Regulation.
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![\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7B24%7D%7B1.14375%7D%3D20.983%5Cfrac%7Brad%7D%7Bs%7D)
Explanation:
Previous concepts
Angular momentum. If we consider a particle of mass m, with velocity v, moving under the influence of a force F. The angular momentum about point O is defined as the “moment” of the particle’s linear momentum, L, about O. And the correct formula is:
![H_o =r x mv=rxL](https://tex.z-dn.net/?f=H_o%20%3Dr%20x%20mv%3DrxL)
Applying Newton’s second law to the right hand side of the above equation, we have that r ×ma = r ×F =
MO, where MO is the moment of the force F about point O. The equation expressing the rate of change of angular momentum is this one:
MO = H˙ O
Principle of Angular Impulse and Momentum
The equation MO = H˙ O gives us the instantaneous relation between the moment and the time rate of change of angular momentum. Imagine now that the force considered acts on a particle between time t1 and time t2. The equation MO = H˙ O can then be integrated in time to obtain this:
![\int_{t_1}^{t_2}M_O dt = \int_{t_1}^{t_2}H_O dt=H_0t2 -H_0t1](https://tex.z-dn.net/?f=%5Cint_%7Bt_1%7D%5E%7Bt_2%7DM_O%20dt%20%3D%20%5Cint_%7Bt_1%7D%5E%7Bt_2%7DH_O%20dt%3DH_0t2%20-H_0t1)
Solution to the problem
For this case we can use the principle of angular impulse and momentum that states "The mass moment of inertia of a gear about its mass center is
".
If we analyze the staritning point we see that the initial velocity can be founded like this:
![v_o =\omega r_{OIC}=\omega (0.15m)](https://tex.z-dn.net/?f=v_o%20%3D%5Comega%20r_%7BOIC%7D%3D%5Comega%20%280.15m%29)
And if we look the figure attached we can use the point A as a reference to calculate the angular impulse and momentum equation, like this:
![H_Ai +\sum \int_{t_i}^{t_f} M_A dt =H_Af](https://tex.z-dn.net/?f=H_Ai%20%2B%5Csum%20%5Cint_%7Bt_i%7D%5E%7Bt_f%7D%20M_A%20dt%20%3DH_Af)
![0+\sum \int_{0}^{4} 20t (0.15m) dt =0.46875 \omega + 30kg[\omega(0.15m)](0.15m)](https://tex.z-dn.net/?f=0%2B%5Csum%20%5Cint_%7B0%7D%5E%7B4%7D%2020t%20%280.15m%29%20dt%20%3D0.46875%20%5Comega%20%2B%2030kg%5B%5Comega%280.15m%29%5D%280.15m%29)
And if we integrate the left part and we simplify the right part we have
![1.5(4^2)-1.5(0^2) = 0.46875\omega +0.675\omega=1.14375\omega](https://tex.z-dn.net/?f=1.5%284%5E2%29-1.5%280%5E2%29%20%3D%200.46875%5Comega%20%2B0.675%5Comega%3D1.14375%5Comega)
And if we solve for
we got:
![\omega =\frac{24}{1.14375}=20.983\frac{rad}{s}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7B24%7D%7B1.14375%7D%3D20.983%5Cfrac%7Brad%7D%7Bs%7D)
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La ciencia y la ingeniería conciben el mundo como comprensible, con reglas que gobiernan su funcionamiento y que a través de un estudio cuidadoso y sistemático se puede evidenciar mediante patrones consistentes que permitan la oportunidad de examinar las características fundamentales que mejor describen los fenómenos.
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