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enyata [817]
3 years ago
9

Explain why you chose the final design of your prototype and how it solved the identified need

Engineering
1 answer:
Nataliya [291]3 years ago
5 0

Answer:

The final design of the prototype is solving the many needs. This is the true aspect of the any Project.

Explanation:

Prototype is draft version of product.

This design allows to explore the ideas and scoping  over design.

Point the  solved issue on the product or the purpose of execution.

This design with proper plan or execution for further actions and demand.

The concepts to the investor before they invest the money.

Clear and precise models on the each section of project.

The project may , the education project, the engineering project or any social activity project.  

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Answer:

2) phone

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Explanation:

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We need to design a logic circuit for interchanging two logic signals. The system has three inputs I1I1, I2I2, and SS as well as
Salsk061 [2.6K]

Explanation:

Inputs and Outputs:

There are 3 inputs = I₁, I₂, and S

There are 2 outputs = O₁ and O₂

The given problem is solved in three major steps:

Step 1: Construct the Truth Table

Step 2: Obtain the logic equations using Karnaugh map

Step 3: Draw the logic circuit

Step 1: Construct the Truth Table

The given logic is

When S = 0 then O₁ = I₁ and O₂ = I₂

When S = 1 then O₁ = I₂ and O₂ = I₁

I₁     |     I₂     |    S    |    O₁    |    O₂

0     |     0     |    0    |    0    |     0

0     |     0     |    1     |    0    |     0

0     |     1      |    0    |    0    |     1

0     |     1      |    1     |    1     |     0

1      |     0     |    0    |    1     |     0

1      |     0     |    1     |    0    |     1

1      |     1      |    0    |    1     |     1

1      |     1      |    1     |    1     |     1

Step 2: Obtain the logic equations using Karnaugh map

Please refer to the attached diagram where Karnaugh map is set up.

The minimal SOP representation for output O₁

$ O_1 = I_1 \bar{S}  + I_2 S $

The minimal SOP representation for output O₂

$ O_2 = I_2 \bar{S}  + I_1 S $

Step 3: Draw the logic circuit

Please refer to the attached diagram where the circuit has been drawn.

7 0
3 years ago
A hole of diameter D = 0.25 m is drilled through the center of a solid block of square cross section with w = 1 m on a side. The
attashe74 [19]

Answer:

q=4.013\:\:kW\\\\T_1=278.91\:\:^{\circ}C\\\\T_2=275.82\:\:^{\circ}C

Explanation:

R_{conv,1}=(h_1\pi D_1L)^{-1}=(50*0.25*2)^{-1}=0.01273\:\:K/W\\\\R_{conv,2}=(h^2*4wL)^{-1}=(4*4*1)^{-1}=0.0625\:\:K/W\\\\R_{cond(2D)}=(Sk)^{-1}=(8.59*150)^{-1}=0.00078\:\:K/W

So, heat rate can be calculated as follows:

q=\frac{T_{\infty,1}-T_{\infty,2}}{R_{conv,1}+R_{conv,2}+R_{cond(2D)}} =\frac{330-25}{0.076} =4.013\:\:kW

Surface temperatures can be calculated as follows:

T_1=T_{\infty,1}-qR_{conv,1}=330-51.09=278.91\:\:^{\circ}C\\\\T_2=T_{\infty,2}+qR_{conv,2}=25+250.82=275.82\:\:^{\circ}C

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Explanation:

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