well, the triangle is an isosceles, so it twin sides, and the twin sides make twin angles, as we see by the tickmarks on A and C, meaning AB = BC.
![\bf x+4=3x-8\implies 4=2x-8\implies 12=2x\implies \cfrac{12}{2}=x\implies 6=x \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ AC\implies x+4\implies 6+4\implies 10](https://tex.z-dn.net/?f=%5Cbf%20x%2B4%3D3x-8%5Cimplies%204%3D2x-8%5Cimplies%2012%3D2x%5Cimplies%20%5Ccfrac%7B12%7D%7B2%7D%3Dx%5Cimplies%206%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20%5Crule%7B34em%7D%7B0.25pt%7D%5C%5C%5C%5C%20AC%5Cimplies%20x%2B4%5Cimplies%206%2B4%5Cimplies%2010)
A would be equal to 1 since a is equal to one already
Answer:
B. .002, .03, .6, .9
Step-by-step explanation:
.002 is .002
.03 is .030
.6 is .60
And, .9 is .90
So in conclusion, least to greatest would be .002 , .030 , .60 , then last but not least .90. The option that best matches this is B!
Answer:
Choose f(x) = 11x + 1
Step-by-step explanation:
Note that we will simply plug the value of 2 into the equation for February:
f(2) = 11(2) + 1 = 23
And plug the value of 6 into the equation for June:
f(6) = 11(6) + 1 = 67
Note how the points on the graph seem to match up with these values. If we evaluate following the same style for each:
f(3) = 11(3) + 1 = 34
f(4) = 11(4) + 1 = 45
f(5) = 11(5) + 1 = 56
Note, these values seems to be very close in approximation to the graph points for each month.
The other three functions return values that are just to far away from what are represented in the graph.
Cheers.
