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2 years ago

Solve the system of equations - 6x + 5y = 0 and -5x + 5y = -5 by combining

Mathematics

1 answer:

Anna [14]2 years ago

7 0

9514 1404 393

Answer:

(x, y) = (-5, -6)

Step-by-step explanation:

The coefficients of y are the same, so we can eliminate y by subtracting one equation from the other. Here, we choose to subtract the first from the second, so that the coefficient of x ends up positive.

(-5x +5y) -(-6x +5y) = (-5) -(0)

x = -5 . . . . . . simplify

-6(-5) +5y = 0 . . . . . . substitute x into the first equation

6 +y = 0 . . . . . . . . . . divide by 5

y = -6 . . . . . . subtract 6

The solution to the system of equations is (x, y) = (-5, -6).

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Calculate the price with VAT of the following case.

AlekseyPX

Answer: $427140

Step-by-step explanation:

Firstly, we'll add MP to the profit and this will be:

= Rs 400000 + Rs 20000

= Rs 420000

Since there is a discount of 10%, this will then be:

= 420000 - (10% × 420000)

= 420000 - 42000

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With a VAT of 13%, then the final price will be:

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2 years ago

A girl weighs 5/8 as much as her brother does. If the girl weighs 110 lb, how much does her brother weigh?

fomenos

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3 years ago

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nikitadnepr [17]

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3 years ago

For the funtion f(x)= (x+7)^5, Find f^-1 (x)

quester [9]

Answer:

The inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

Step-by-step explanation:

For the function $f(x)= (x+7)^5$ , Find $f^{-1} (x)$

For finding inverse of x,

First let:

$y=(x+7)^5$

Now replace x with y and y with x

$x=(y+7)^5$

Now, solve for y

Taking 5th square root on both sides

$\sqrt[5]{x}=\sqrt[5]{(y+7)^5}\\\sqrt[5]{x}=y+7\\=> y+7=\sqrt[5]{x}\\y=\sqrt[5]{x}-7$

Now, replace y with $f^{-1} (x)$

$f^{-1} (x)=\sqrt[5]{x}+7$

So, the inverse of function $f(x)= (x+7)^5$ is $\mathbf{f^{-1} (x)=\sqrt[5]{x}+7}$

Option A is correct option.

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