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3 years ago

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A car is traveling down a highway at a constant speed, described by the equationd=65t, where d represents the distance, in miles

, that the car travels at this speed in t hours.
How many miles does the car travel in 1.5 hours?

1 answer:

Rasek [7]3 years ago

4 0

Answer:

97.5 miles

Step-by-step explanation:

you would take 65 and multiply by 1.5

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Explain how you use estimation to check the reasonableness of a solution to a practical problem.

miskamm [114]

Answer:

Estimation is just giving a general answer to the situation and can be specified on specifics depending on the numbers used and whichever question it's asking. But also remember that whenever you estimate your answer will be an approximate answers, not an exact.

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Solve the expression using pemdas (4+5)÷3×4

Dennis_Churaev [7]

1) you add the variables in the bracket

(4+5)÷3×4

9÷3×4

2) you multiply 3 by 4

9÷3×4

9÷12

3) now you divide 9 by 12

9÷12

=0.75

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Pls help with 29..tank you

trapecia [35]

Answer:

See below

Step-by-step explanation:

Let the 2 roots be A and A^2.

Then A^3 = c/a and A + A^2 = -b/a.

Using the identity a^3 b^3 = (a + b)^3 - 3ab^2 - 3a^2b:-

A^3 + (A^2)^3 = ( A + A^2)^3 - 3 A.A^4 - 3 A^2. A^2

= (A + A^2)^3 - 3A*3( A + A^2)

Substituting:-

c/a + c^2/a^2 = (-b/a)^3 - 3 (c/a)(-b/a)

Multiply through by a^3:-

a^2c + ac^2 = -b^3 + 3abc

Factoring:-

ac(a + c) = 3abc - b^3

This is not the formula required in the question but let's see if the formula in the question reduces to this. If it does we have completed the proof.

a(c - b)^3 = a(c^3 - 3c^2b + 3cb^2 - b^3) = ac^3 - 3ac^2b + 3acb^2 - ab^3

c(a - b)^3 = c(a^3 - 3a^2b + 3ab^2 - b^3) = ca^3 - 3a^2bc + 3acb^2 - cb^3.

These are equal so we have

ca^3 - 3a^2bc + 3acb^2 - cb^3 = ac^3 - 3abc^2 + 3acb^2 - ab^3

The 3acb^2 cancel out so we have:-

a^3c - ac^3 = 3a^2bc - 3abc^2 + b^3c - ab^3

ac(a^2 - c^2) = 3abc( a - c) + b^3(c - a)

ac(a + c)(a -c) = 3abc(a - c) - b^3 (a - c)

Divide through by (a - c):-

ac(a + c) = 3abc - b^3 , which is the result we got earlier.

This completes the proof.

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3 years ago

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The question is in the attachment.

Vesna [10]

Answer:

0.0816

Step-by-step explanation:

Given:

Total number of students = 5000
Number of students taking an online class = 1200
Number of students prefer watching baseball to football = 1700

Let O = Students taking an online class

Let B = Students prefer watching baseball to football

Therefore,

P(O) = 1200/5000 = 0.24

P(B) = 1700/5000 = 0.34

If events O and B are independent,

⇒ P(O ∩ B) = P(O) · P(B)

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2 years ago

ANSWER ALL (a-d) FOR 30 POINTS - EASY

djverab [1.8K]

Part a.

<span>The perimeter formula is: </span>P = 2w + 2L

Your answer for part A is P = 2w + 2L

Part b.

They tell us in part b, that:
w = 6L + 20

Substitute that into what we got for part a.

P = 2(6L + 20) + 2L
P = 12L + 40 + 2L
P = 14L + 40

Your answer for partb is P = 14L + 40

Part c.

So we take what we got from part b, and solve for L.

P = 14L + 40
14L = P - 40

$L = \boxed{\frac{P-40}{14}}$

That is your answer for part 3 ^

part d.

Plug in w = 32 into what we first got in part b.

w = 6L + 20
32 = 6L + 20
6L = 12

L = 2

Your answer for part d is L = 2

<span>:D</span>

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3 years ago