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Semmy [17]
3 years ago
8

How many moles of H2O can you make from 16 moles of NaOH

Chemistry
1 answer:
dusya [7]3 years ago
5 0

Answer: 1.     For the reaction: 2K + 0.5 O2 à 1K2O

a. How many moles of O2 are needed to react with 0.56 moles of K?

0.56 moles of K  

b. How many moles of O2 are needed to make 7.6 g of K2O?

7.6 g K2O (mole/94g K2O) = 0.0809 moles K2O

0.0809 moles K2O

c. How many grams of K2O will be produced from 0.50 g of K?

0.50 g K (mole/39g K) = 0.0128 moles K

0.0128 moles K

x = 0.0064 moles K2O (78+16)g/mole =  0.60 g

2.     For the reaction: Na2O + H2O à2 NaOH

a. What mass NaOH could be made from 12.4 g of Na2O?

12.4 g of Na2O (mole/62 g) = 0.2 mole Na2O

0.2 mole Na2O

0.4 moles NaOH(40 g/mole) = 16 g NaOH

b. How many moles of Na2O are needed to make 1000 g of NaOH?

1000g (mole/40 g) = 25 moles NaOH

25 moles NaOH

c. What would happen if 18 g of water were mixed with 18 g of sodium oxide?

18 g of H2O is 1 mole

18 g of Na2O = 18g(mole/62g) =0.29 moles

but according to the equation water and sodium oxide react in a 1:1, so we have too much water . All 0.29 moles of  Na2O will react with only 0.29 moles of water to create twice as many moles of NaOH (see ratio). Answer = 0.58 moles of NaOH result.

0.58 moles(40 g/mole) = 23.2 g

3.     Balance and answer the questions that follow:

C + 2 H2àCH4

a. How many moles of CH4 can be made from 7.0 g of H2?

7.0 g of H2= 3.5 moles H2. How? Divide by molar mass of diatomic hydrogen.

From the ratio, only half as many moles of methane will be produced so answer = 1.75 moles CH4.

b. What weight of H2 is needed to react with 5.0 g of C?

Convert 5.0 g of C to moles: 0.417 moles C

From ratio: 0.834 moles of H2 is needed.

Convert to mass by multiplying by molar mass:

1.66 g H2

c. What would happen if 20 g of hydrogen were mixed with 20 g of carbon?

20 g of C(mole/12 g) = 1.67 mole C. This amount needs 2(1.75 moles) = 3 moles of H2.(see ratio). We clearly have an excess of H2 since 20 g = 10 moles.

The amount of CH4 produced will depend on C, the limiting reagent, and only 1.67e moles of CH4 will be produced.

1.67 moles (16g/mole) = 27 g

Explanation:

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8 0
1 year ago
The following data is given to find the formula of a Hydrate:
umka21 [38]

The masses can be found by substractions:

  • Mass of CaSO₄.H2O (hydrate):

16.05 g - 13.56 g = 2.49 g

  • Mass of CaSO₄ anhydrate:

15.07 g - 13.56 g = 1.51 g

  • The mass of water is equal to the difference between the mass of the hydrate and the mass of the anhydrate:

2.49 g - 1.51 g = 0.98 g

  • The percent of water is found by the formula:

massWater ÷ massHydrate * 100%

0.98 g ÷ 2.49 g * 100% = 39.36%

  • The mole of water is calculated using water's molecular weight (18g/mol):

0.98 g ÷ 18 g/mol = 0.054 mol water

  • A similar procedure is made for the mole of salt (CaSO₄ = 136.14 g/mol)

1.51 g ÷ 136.14 g/mol = 0.011 mol CaSO₄

  • The ratio of mole of water to mole of anhydrate is:

0.054 mol water / 0.011 mol CaSO₄ = 0.49

In other words the molecular formula for the hydrate salt is CaSO₄·0.5H₂O

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3 years ago
Write the IUPAC names for the following compounds.
atroni [7]
Benzine
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5 0
2 years ago
In a titration, 4.7 g of an acid (HX) requires 32.6 mL of 0.54 M NaOH(aq) for complete reaction. What is the molar mass of the a
katrin2010 [14]

Answer : The molar mass of an acid is 266.985 g/mole

Explanation : Given,

Mass of an acid (HX) = 4.7 g

Volume of NaOH = 32.6 ml = 0.0326 L

Molarity of NaOH = 0.54 M = 0.54 mole/L

First we have to calculate the moles of NaOH.

\text{Moles of }NaOH=\text{Molarity of }NaOH\times \text{Volume of solution}=0.54mole/L\times 0.0326L=0.017604mole

Now we have to calculate the moles of an acid.

In the titration, the moles of an acid will be equal to the moles of NaOH.

Moles of an acid = Moles of NaOH = 0.017604 mole

Now we have to calculate the molar mass of and acid.

\text{Moles of an acid}=\frac{\text{Mass of an acid}}{\text{Molar mass of an acid}}

Now put all the given values in this formula, we get:

0.017604mole=\frac{4.7g}{\text{Molar mass of an acid}}

\text{Molar mass of an acid}=266.985g/mole

Therefore, the molar mass of an acid is 266.985 g/mole

3 0
3 years ago
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