1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Semmy [17]
3 years ago
8

How many moles of H2O can you make from 16 moles of NaOH

Chemistry
1 answer:
dusya [7]3 years ago
5 0

Answer: 1.     For the reaction: 2K + 0.5 O2 à 1K2O

a. How many moles of O2 are needed to react with 0.56 moles of K?

0.56 moles of K  

b. How many moles of O2 are needed to make 7.6 g of K2O?

7.6 g K2O (mole/94g K2O) = 0.0809 moles K2O

0.0809 moles K2O

c. How many grams of K2O will be produced from 0.50 g of K?

0.50 g K (mole/39g K) = 0.0128 moles K

0.0128 moles K

x = 0.0064 moles K2O (78+16)g/mole =  0.60 g

2.     For the reaction: Na2O + H2O à2 NaOH

a. What mass NaOH could be made from 12.4 g of Na2O?

12.4 g of Na2O (mole/62 g) = 0.2 mole Na2O

0.2 mole Na2O

0.4 moles NaOH(40 g/mole) = 16 g NaOH

b. How many moles of Na2O are needed to make 1000 g of NaOH?

1000g (mole/40 g) = 25 moles NaOH

25 moles NaOH

c. What would happen if 18 g of water were mixed with 18 g of sodium oxide?

18 g of H2O is 1 mole

18 g of Na2O = 18g(mole/62g) =0.29 moles

but according to the equation water and sodium oxide react in a 1:1, so we have too much water . All 0.29 moles of  Na2O will react with only 0.29 moles of water to create twice as many moles of NaOH (see ratio). Answer = 0.58 moles of NaOH result.

0.58 moles(40 g/mole) = 23.2 g

3.     Balance and answer the questions that follow:

C + 2 H2àCH4

a. How many moles of CH4 can be made from 7.0 g of H2?

7.0 g of H2= 3.5 moles H2. How? Divide by molar mass of diatomic hydrogen.

From the ratio, only half as many moles of methane will be produced so answer = 1.75 moles CH4.

b. What weight of H2 is needed to react with 5.0 g of C?

Convert 5.0 g of C to moles: 0.417 moles C

From ratio: 0.834 moles of H2 is needed.

Convert to mass by multiplying by molar mass:

1.66 g H2

c. What would happen if 20 g of hydrogen were mixed with 20 g of carbon?

20 g of C(mole/12 g) = 1.67 mole C. This amount needs 2(1.75 moles) = 3 moles of H2.(see ratio). We clearly have an excess of H2 since 20 g = 10 moles.

The amount of CH4 produced will depend on C, the limiting reagent, and only 1.67e moles of CH4 will be produced.

1.67 moles (16g/mole) = 27 g

Explanation:

You might be interested in
Which statement accurately describes dark matter?
Mandarinka [93]

Answer:

C. It does not emit electromagnetic radiation.

Explanation:

Right now, Dark Matter is only a theory. Scientist proposed this to counter some of the strange phenomenon with matter in space.

Scientists know little about dark matter. Some say it's one of the driving forces of the universe. Currently, scientists have no way of measuring or identifying dark matter.

5 0
3 years ago
Read 2 more answers
Why is it so important to use more than just fossil fuels for our energy sources?​
blsea [12.9K]

Answer:

Fossil Fuels have the ability to pollute and trash our ecosystems. Its better for us to use clean and renewable energy too.

Explanation:

8 0
3 years ago
How many grams of h2 will be produced if 175g of HCI are allowed to react completely with sodium
Sedbober [7]

Answer:

4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium

Explanation:

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) you can see that the following amounts in moles of each compound react and are produced:

  • HCl: 2 moles
  • Na: 1 mole
  • NaCl: 2 moles
  • H₂: 1 mole

You know the following masses of each element:

  • H: 1 g/mole
  • Cl: 35.45 g/mole
  • Na: 23 g/mole

So, the molar mass of each compound participating in the reaction is:

  • HCl: 1 g/mole + 35.45 g/mole= 36.45 g/mole
  • Na: 23 g/mole
  • NaCl: 23 g/mole + 35.45 g/mole= 58.45 g/mole
  • H₂: 2* 1 g/mole= 2 g/mole

Then, by stoichiometry of the reaction, the following amounts in grams of each of the compounds participating in the reaction react and are produced:

  • HCl: 2 moles* 36.45 g/mole= 72.9 g
  • Na: 1 mole* 23 g/mole= 23 g
  • NaCl: 2 moles* 58.45 g/mole= 116.9 g
  • H₂: 1 mole* 2 g/mole= 2 g

So, a rule of three applies as follows: if by stoichiometry, when reacting 72.9 grams of HCl 2 grams of H₂ are formed, when reacting 175 grams of HCl how much mass of H₂ will be formed?

mass of H_{2} =\frac{175 g of HCl*2g ofH_{2} }{72.9 g of HCl}

mass of H₂= 4.8 g

<u><em>4.8 grams of H₂ will be produced if 175g of HCI are allowed to react completely with sodium</em></u>

3 0
3 years ago
Read 2 more answers
Which color would have the shortest wavelength?!<br>A) red<br>B) yellow<br>C) green<br>D)blue
aliya0001 [1]
D) blue

(about 400 nanometers)
8 0
3 years ago
Does apple juice have acid
stepladder [879]
Yes, it has many natural acids. However, the biggest and most prominent acid is the organic acid, malic acid.
8 0
4 years ago
Other questions:
  • Why is it advantageous to produce plutonium -239
    8·2 answers
  • Calculate OH- given H3 O+ = 1.40 *10^-4 M
    8·1 answer
  • what is the position of an element in the periodic table if its electrons configuration is 1s2 2s2 2p6 3s2 3p5?
    10·1 answer
  • An unknown compound has the empirical formula CH2O and a molecular mass of 180 amu. What is the molecular formula of the compoun
    13·1 answer
  • If Earth is pulling down on you, are you pulling up on Earth?
    12·2 answers
  • How many grams are in 2.3 x 10^-4 moles of Ca3(PO4)2
    10·1 answer
  • Which particles can be stopped by human skin?
    5·1 answer
  • SO2Cl2 decomposes in a first-order process with a half-life of 4.88 × 103 s. If the original concentration of SO2Cl2 is 0.011 M,
    15·1 answer
  • How many lunar phases are there?
    8·1 answer
  • What attracts heat more? black or aluminum foil?​
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!