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lutik1710 [3]
3 years ago
14

This figure consists of a rectangle and semicircle

Mathematics
2 answers:
Norma-Jean [14]3 years ago
6 0

Answer:

26.1732

Step-by-step explanation:

Pretty sure supper supper sorry if it is wrong  

dedylja [7]3 years ago
3 0

Answer:

\huge\boxed{\sf Area \ of \ the \ figure =38.1cm\²}

Step-by-step explanation:

<u>Area of rectangle:</u>

= Length * Width

Where length = 4, Width = 6

= 4 * 6

= 24 cm²

<u>Area of semi-circle:</u>

Diameter = 6 cm

Radius = D/2 = 6/2 = 3 cm

Area = πr² / 2

Area = (3.14)(3)²/2

Area = (3.14)(9) / 2

Area = 28.3 / 2

Area = 14.1 cm²

<u>Area of the whole figure:</u>

= Area of the rectangle + Area of the semi-circle

= 24 + 14.1

= 38.1 cm²

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
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