In order for two lines to be parallel, they must have the dame slope. In this case, it is 7/6. So the new line Will have the next form:
y = 7/6x + b
Now, assuming that the new line passes through the point (1,1):
1 = 7/6*1 + b
b = -0.17
Replacing b:
y = 7/6x - 0.17
<h2>1.</h2>
Firstly, combine like terms: 
Next, subtract r on both sides of the equation: 
Next, add 8 onto both sides of the equation: 
Lastly, divide both sides by 6 and <em><u>your answer will be r = 3.</u></em>
<h2>2.</h2>
Firstly, multiply both sides by e: 
Lastly, divide both sides by 3, and <em><u>your answer will be 
</u></em>
You have not provided the diagram/coordinates for point Q, therefore, I cannot provide an exact answer.
However, I can help you with the concept.
When rotating a point 90° counter clock-wise, the following happens:
coordinates of the original point: (x,y)
coordinates of the image point: (-y,x)
Examples:
point (2,5) when rotated 90° counter clock-wise, the coordinates of the image would be (-5,2)
point (1,9) when rotated 90° counter clock-wise, the coordinates of the image would be (-9,1)
point (7,4) when rotated 90° counter clock-wise, the coordinates of the image would be (-4,7)
Therefore, for the given point Q, all you have to do to get the coordinates of the image is apply the transformation:
(x,y) .............> are changed into.............> (-y,x)
Hope this helps :)
Use pythagora's theorem to test if it is a right triangle
c^2 = a^2 + b^2
65^2 = 52^2 + 43^2
4225 = 2704 + 1849
4225 =/= 4553
therefore it is not a right triangle as it does not comply to pythagora's theorem
