HELP ME PLEASEEE ITS GEOMETRY!!!

Given the function f(x) = x - 4, find f(-2).

Mars2501 [29]

Answer: f(-2) = -6

Step-by-step explanation: f(-2) = -2 -4

f(-2) = -6

6 0

2 years ago

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points. Rachel scored 78 p

Artemon [7]

Answer:

Keenan's z-score was of 0.61.

Rachel's z-score was of 0.81.

Step-by-step explanation:

Z-score:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Keenan scored 80 points on an exam that had a mean score of 77 points and a standard deviation of 4.9 points.

This means that $X = 80, \mu = 77, \sigma = 4.9$

So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{80 - 77}{4.9}$

$Z = 0.61$

Keenan's z-score was of 0.61.

Rachel scored 78 points on an exam that had a mean score of 75 points and a standard deviation of 3.7 points.

This means that $X = 78, \mu = 75, \sigma = 3.7$ . So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{75 - 78}{3.7}$

$Z = 0.81$

Rachel's z-score was of 0.81.

6 0

2 years ago

CAN YOU PLZZZZZZZZZ HELP ME WITH THIS

satela [25.4K]

$\huge\text{Hey there!}$

$\large\text{Here is your GUIDE for you to go by}\downarrow$

$\bullet\bold{\ \geq \ or \leq \ will\ have\ a\ \underline{CLOSED}\ or\ \underline{SHADED\ circle}}\\\bullet\bold{\ >\ or\ \ or$

$\bold{\ Random\ GUIDE\ \#2}\downarrow$

$\bold{1. \geq is\ GREATER\ or\ EQUAL\ TO}\\\bold{2. \leq\ is\ LESS\ or\ EQUAL\ TO}\\\bold{3. >\ is\ GREATER\ THAN}\\\bold{4. < \ is\ LESS\ THAN}$

“ $\bold{6>x}$ ”

$\bold{Well, based\ on\ your\ GUIDE\ we\ can do\ PROCESS\ OF\ ELIMINATION.}\\\\\bold{REMEMBER: < or > will\ have\ a\ O P E N E D\ circle.\ This\ throws\ A\ \& C}\\\bold{as\ your\ results\ because\ they\ are\ CLOSED\ CIRCLES\ and\ we\ are}\\\bold{looking\ for\ O P E N E D\ circles. This\ leads\ B\ & D\ as\ your\ POSSIBLE}\\\bold{result}$

$\bold{>\ equals \ GREATER\ THAN}$

$\bold{Graph\ B.\ is\ SHADED\ to\ the\ LEFT\ which\ we\ need}$

$\bold{Graph\ D.\ would\ be\ TOO\ BIG}$

$\boxed{\boxed{\bold{Answer: Option\ B.\ }}}\huge\checkmark$

$\textsf{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite40:)}$

4 0

2 years ago

Read 2 more answers

Sometimes, always, or never true?:14x+3x-7=7x+7-4x

kobusy [5.1K]

Always will be your answer ;D

4 0

2 years ago

The angle of elevation from an observer to the bottom edge of the Delaware River drawbridge observation deck located 200 feet fr

aleksklad [387]

The height of the chimney above the floor of the observation deck is 52.4 ft

Two right angle triangle will be formed.

<h3>Right angle triangle:</h3>

Right angle triangle are triangle that has one of its angle as 90 degrees.

Therefore, using trigonometric ratio,

adjacent side = distance of observer from the bottom edge of the Delaware River drawbridge observation deck

Therefore,

tan 40 = opposite / adjacent

Where

x = height of the observer to the top of the observation deck

tan 40 = x / 200

x = 200 tan 40

x = 167.819926235

x = 167.82 ft

tan 30 = opposite / adjacent

y = height of the observer to the bottom of the observation deck

tan 30 = y / 200

y = 200 tan 30

y = 115.470053838

y = 115.47 ft

The height of the chimney above the floor of the observation deck = height of the observer to the top of the observation deck - height of the observer to the bottom of the observation deck

The height of the chimney above the floor of the observation deck = 167.82 - 115.47 = 52.35 ft

learn more on trigonometric ratio here: brainly.com/question/23854119

5 0

2 years ago