The value of r so the line that passes through (-5,2) and (3,r) has a slope of -1/2 is -2
<u>Solution:</u>
Given that line is passing through point (-5, 2) and (3, r)
Slope of the line is 
Need to determine value of r.
Slope of a line passing through point 
is given by following formula:
--- eqn 1
On substituting the given value in (1) we get
Hence the value of "r" is -2
Set up a proportion
3 coins:8 notes and then the other one 24 coins : x (unknown notes)
they have a relationship so we can set them equal to each other.
3/8=24/x cross multiply: 8 * 24 = 192
Now divide that by 3: 192/3 = 64
So there are 64 notes in the bag
Answer:
<u>y = w and ΔABC ~ ΔCDE</u>
Step-by-step explanation:
Given sin(y°) = cos(x°)
So, ∠y + ∠x = 90° ⇒(1)
And as shown at the graph:
ΔABC is aright triangle at B
So, ∠y + ∠z = 90° ⇒(2)
From (1) and (2)
<u>∴ ∠x = ∠z </u>
ΔCDE is aright triangle at D
So, ∠x + ∠w = 90° ⇒(3)
From (1) and (3)
<u>∴ ∠y = ∠w</u>
So, for the triangles ΔABC and ΔCDE
- ∠A = ∠C ⇒ proved by ∠y = ∠w
- ∠B = ∠D ⇒ Given ∠B and ∠D are right angles.
- ∠C = ∠E ⇒ proved by ∠x = ∠z
So, from the previous ΔABC ~ ΔCDE by AAA postulate.
So, the answer is <u>y = w and ΔABC ~ ΔCDE</u>
Answer:
3(2 - y)(2 + y)(4 + y²)
Step-by-step explanation:
48 - 3y⁴
Take 3 common:
3(16 - y⁴)
16 is 4² and y⁴ is (y²)²
3(4² - (y²)²)
Using a² - b² = (a - b)(a + b)
3(4 - y²)(4 + y²)
Again, 4 = 2²
3(2² - y²)(4 + y²)
3(2 - y)(2 + y)(4 + y²)
