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matrenka [14]
3 years ago
15

Help please! Identify a set of parallel and a set of perpendicular lines in this image.

Mathematics
2 answers:
zmey [24]3 years ago
5 0

Answer:

the 3th option

Step-by-step explanation:

hope it help you

KatRina [158]3 years ago
4 0

Answer:

Option 1.

(I don't really have any explanation to add on)

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Delicious77 [7]

Answer:

it is C! if I were to write t<6 on a number line it would be open circle above 6 and going to the left since it is smaller than 6!

8 0
2 years ago
I don’t understand because it confused me
tamaranim1 [39]
Smaller and higher
Is the answer hope it helps if you are still confused ask
7 0
4 years ago
Find the slope. NEED HELP ASAP PLEASE !!!!
chubhunter [2.5K]

Answer:

sure i gotchu

Step-by-step explanation:

3/2

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5 0
3 years ago
So is anyone good at geometry ive posted this before but i was used for points i need help
SOVA2 [1]
Answers:
Reason 3: Definition of Parallelogram
Reason 4: Alternate Interior Angles Theorem
Reason 5: Reflexive Property of Congruence
Reason 6: ASA Congruence Property

------------------------------------------------------

Explanations:

Explanation for Reason 3: A parallelogram, by definition, has opposite sides that are parallel. It's built into the name more or less. Sides AB and CD are opposite one another in the parallelogram so they are parallel segments

Explanation for Reason 4: Angle ABD is congruent to angle CDB because they are alternate interior angles. They are on the inside of the "train tracks" that are formed by AB and CD. They lay on opposite sides of the transversal BD

Explanation for Reason 5: Any segment is congruent to itself; ie, the same length

Explanation for Reason 6: Using reasons 2,5 and 4, we can use ASA (angle side angle) to prove the two triangles ABD and CDB congruent. Reason 2 is the first "A" in ASA. Reason 5 is the S in ASA. Reason 4 is the other A in ASA. The side is between the two pairs of angles. See the attache image for a visual summary of how ASA is being used.

8 0
3 years ago
Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4%
bogdanovich [222]

Mr. Jackson invested $800 at 6% per year and $ 2400  at 4 % per year

<h3><u>Solution:</u></h3>

Mr. Jackson invested a sum of money at 6% per year, and 3 times as much at 4% per year.

Let the sum invested be ‘a’ and ‘3a’ at 6% per year and 4 % per year respectively

Also, his annual return totaled $144

We can form following equation on the basis of question:-

\begin{array}{l}{\text { Then, } \frac{a \times 6 \times 1}{100}+\frac{3 a \times 4 \times 1}{100}=\$ 144} \\\\ {\frac{6 a}{100}+\frac{12 a}{100}=144} \\\\ {\frac{6 a+12 a}{100}=144} \\\\ {\frac{18 a}{100}=144} \\\\ {18 a=14400} \\\\ {a=14400 \div 18}\end{array}

a = $800

The amount of money invested at 6% = a = 800

The amount of money invested at 4 % = 3a = 3(800) = 2400

So, the amount of money invested at 6% is $800 and the amount of money invested at 4% is $ 2400

4 0
3 years ago
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