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Firlakuza [10]
3 years ago
5

Please help! Will mark brainliest if correct! Use the model attached to answer

Mathematics
2 answers:
iogann1982 [59]3 years ago
6 0

Answer:

4 cubes will be shown in the right view of the model and the 1st option is the top view for the model.

N76 [4]3 years ago
5 0
A and b I think I hope
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Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?
tiny-mole [99]

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

5 0
3 years ago
Antonio runs 4 miles each day. How
Tom [10]
Antonio runs 1,460 miles in one year
6 0
3 years ago
Read 2 more answers
Which of the following coordinates are not correctly named based on the image?
timama [110]

Answer:

Hi, there the answer is (4,2)

Step-by-step explanation:

The reason is that 4 is the y-axis and 2 is the x-axis and

the rule is x is first then y

The correct format for writing this it is supposed to be (2,4).

Therefore, your answer will (4,2)

3 0
3 years ago
Find the LCM (least common multiple) of (5x-9) and (3x+8)
bixtya [17]
LCM((5x-9),(3x+8))=(5x-9)(3x+8)
3 0
3 years ago
To find the measure of ∠A in ∆ABC, use the___(Pythagorean Theorem, Law of Sines, Law of Cosines). To find the length of side HI
nadya68 [22]

<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use

we know that

In the triangle ABC

Applying the law of sines

\frac{a}{sin\ A}=\frac{b}{sin\ B}=\frac{c}{sin\ C}

in this problem we have

\frac{a}{sin\ A}=\frac{b}{sin\ theta}\\ \\a*sin\ theta=b*sin\ A\\ \\ sin\ A=\frac{a*sin\ theta}{b} \\ \\ A=arc\ sin (\frac{a*sin\ theta}{b})

therefore

<u>the answer  Part 1) is</u>

Law of Sines

<u>Part 2) </u>To find the length of side HI in ∆HIG, use

we know that

In the triangle HIG

Applying the law of cosines

g^{2}=h^{2}+i^{2}-2*h*i*cos\ G

In this problem we have

g=HI

G=angle Beta

substitute

HI^{2}=h^{2}+i^{2}-2*h*i*cos\ Beta

HI=\sqrt{h^{2}+i^{2}-2*h*i*cos\ Beta}

therefore

<u>the answer Part 2) is</u>

Law of Cosines

3 0
3 years ago
Read 2 more answers
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