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garri49 [273]
3 years ago
11

What is the greatest common factor (GCF) of 40 and 42?

Mathematics
1 answer:
enot [183]3 years ago
7 0
Answer: GCF of 40 and 42 is 2
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Um there's no way for me to tell because you don't have the information
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Whoever gets it right can have brainliest, but answer ASAP!
sveta [45]

Answer:

-29

Step-by-step explanation:

(-4 + -3) x 2^2 - 1

follow order of operations PEMDAS

Parentheses:

(-4 + -3) x 2^2 - 1

(-7) x 2^2 -1

exponents:

(-7) x 4 - 1

multiplication

-28 - 1

subtraction

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3 0
2 years ago
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Which expression represents the distance between the two points, X and Y, on the number line
balandron [24]
The expression representing the distance is
0
7 0
3 years ago
Punctele O, A, B, C sunt coliniare în această ordine, iar segmentele OA, AB și BC au lungimile exprimate în cm, prin numere natu
julia-pushkina [17]

Răspuns:

a) OC = 18cm

b) MN = 6cm

Explicație pas cu pas:

Găsiți diagrama la întrebarea atașată.

a) Din diagramă se poate observa că OC = OA + AB + AC

OC = 2n + 2n + 2 + 2n + 4

OC = 6n + 6

Următorul este să obțineți valoarea lui n:

OM = OA + AM

Să obținem segmentul AM;

Deoarece M este segmentul mijlociu al AC, atunci;

AM = AC / 2

AM = AB + BC / 2

AM = 2n + 2 + 2n + 4/2

AM = 4n + 6/2

AM = 2n + 3

Din moment ce OM = OA + AM

OM = 2n + 2n + 3

OM = 4n + 3

Dat fiind OM = 11

11 = 4n + 3

4n = 11-3

4n = 8

n = 2

Următorul pas este să calculați OC;

OC = 6n + 6

OC = 6 (2) + 6

OC = 18

Prin urmare, lungimea segmentului OC este de 18 cm

b) Această întrebare ne cere să găsim segmentul de linie MN.

Din diagramă, MN = AM - AN

Deoarece AM = 2n + 3 din întrebarea 1;

AM = 2 (2) +3

AM = 4 + 3

AM = 7

Acum, să obținem AN:

Din diagramă, AN = ON-OA și ON = OB / 2

AN = OB / 2 - OA

AN = (2n + 2n + 2) / 2 - 2n

AN = 4n + 2/2 - 2n

AN = 2n + 1 - 2n

AN = 2n-2n + 1

AN = 1

De la MN = AM - AN

MN = 7 - 1

MN = 6cm

Prin urmare, distanța dintre N, mijlocul segmentului OB și punctul M este de 6cm

6 0
3 years ago
What are the values of a and b?
ivann1987 [24]

Answer:

<h2>a = 400/21, b = 580/21</h2>

Step-by-step explanation:

Small triangles are similar. Therefore, the sides are proportional

\dfrac{a}{20}=\dfrac{20}{21}               <em>cross multiply</em>

21a=(20)(20)       <em>divide both sides by 21</em>

a=\dfrac{400}{21}

For b, we can use the Pythagorean theorem:

b^2=\left(\dfrac{400}{21}\right)^2+20^2\\\\b^2=\dfrac{160000}{441}+400\\\\b^2=\dfrac{160000}{441}+\dfrac{176400}{441}\\\\b^2=\dfrac{336400}{441}\to b=\sqrt{\dfrac{336400}{441}}\\\\b=\dfrac{\sqrt{336400}}{\sqrt{441}}\\\\b=\dfrac{580}{21}

3 0
3 years ago
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