All categories

3 years ago

Solve the equation negative 3X +9 equals three(2x+3) + 3(x-4) + 1

Mathematics

1 answer:

timofeeve [1]3 years ago

5 0

Answer:

Step-by-step explanation:

-3x+9=3(2x+3)+3(x-4)+1

Distributive property in the parenthesis

-3x+9=6x+9+3x-12+1

Combine Like Terms

-3x+9=9x-2

Get the x’s on one side

-3x+9=9x-2

+3. +2 +3. +2

11=11x

Divide by 11 on both sides

11/11=1

You might be interested in

Fast i need it thanks

Troyanec [42]

Answer:

trigonometry is difficult haha…. Answer is 8.81 I think

Step-by-step explanation:

5 0

2 years ago

PLZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZZ HELP ME THIS IS SO CONFUSING AND I DON'T UNDERSTAND ANYTHING PL

Leto [7]

Answer:

i got -2y + 3/2 x + 7/4

so I think is d

5 0

3 years ago

-8.46 greater or less than 5.31

Gekata [30.6K]

Hello.

-8.46 is less than 5.31, because it is negative.

4 0

3 years ago

Read 2 more answers

K=mv^2/2 solve for v

matrenka [14]

Answer: $v=\sqrt[]{\frac{2K}{m} }$

Step-by-step explanation:

$K=\frac{mv^2}{2}$

First, multiply by 2 to get rid of the 2 in the denominator. Remember that if you make any changes you have to make sure the equation keeps balanced, so do it on both sides as following;

$2*K=\frac{mv^2}{2}*2$

$2K=mv^2$

Divide by m to isolate $v^2$ .

$\frac{2K}{m}=\frac{mv^2}{m}$

$\frac{2K}{m} =v^2$

To eliminate the square and isolate v, extract the square root.

$\sqrt[]{\frac{2K}{m} }=\sqrt[]{v^2}$

$\sqrt[]{\frac{2K}{m} }=v$

let's rewrite it in a way that v is in the left side.

$v=\sqrt[]{\frac{2K}{m} }$

4 0

3 years ago

how do I find the area of an equilateral triangle given the perimeter of 60 and the height of 17.3 cm?

guajiro [1.7K]

If perimeter is 60 so the side is 60 ÷ 3 = 20

Now we can apply the area formula for triangles;

$A=\frac{1}{2}.b.h\\
\\
A=\frac{1}{2}.20.17.3=10.17.3=173 \ cm^2$

3 0

3 years ago