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frez [133]
3 years ago
9

Unit: Proportional Relationships

Mathematics
1 answer:
Crank3 years ago
3 0

Answer:

i have no idea

Step-by-step explanation:

You might be interested in
R
Shalnov [3]

Answer:

x = 54

y = 47.5

Step-by-step explanation:

If two lines p and q are parallel and line r is a transversal intersecting these lines at two different points,

(x + 56)° = (2x + 2)° [corresponding angles]

2x - x = 56 - 2

x = 54

Similarly, lines r and s are parallel lines and q is a transversal line intersecting these lines,

(y + 7)° + (3y - 17)°= 180° [Consecutive exterior angles]

4y - 10 = 180

4y = 190

y = 47.5

3 0
2 years ago
David makes 17 dollars in an hour and works 25 hours a week.linda makes 25 dollars a hour abd works 7 hours each week. How much
Soloha48 [4]

Step-by-step explanation:

David makes 17(25)

and

Linda maked 25(7)

so it would make the equation 17(25)+25(7)

425+175 together they would be making

600 dollars a week

6 0
3 years ago
Solve the given initial-value problem. x^2y'' + xy' + y = 0, y(1) = 1, y'(1) = 8
Kitty [74]
Substitute z=\ln x, so that

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\mathrm dy}{\mathrm dz}\cdot\dfrac{\mathrm dz}{\mathrm dx}=\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}

\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)

Then the ODE becomes


x^2\dfrac{\mathrm d^2y}{\mathrm dx^2}+x\dfrac{\mathrm dy}{\mathrm dx}+y=0\implies\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)+\dfrac{\mathrm dy}{\mathrm dz}+y=0
\implies\dfrac{\mathrm d^2y}{\mathrm dz^2}+y=0

which has the characteristic equation r^2+1=0 with roots at r=\pm i. This means the characteristic solution for y(z) is

y_C(z)=C_1\cos z+C_2\sin z

and in terms of y(x), this is

y_C(x)=C_1\cos(\ln x)+C_2\sin(\ln x)

From the given initial conditions, we find

y(1)=1\implies 1=C_1\cos0+C_2\sin0\implies C_1=1
y'(1)=8\implies 8=-C_1\dfrac{\sin0}1+C_2\dfrac{\cos0}1\implies C_2=8

so the particular solution to the IVP is

y(x)=\cos(\ln x)+8\sin(\ln x)
4 0
3 years ago
Pls answer x-24=58; x=82<br>yes I know its easy
MatroZZZ [7]
I think you solved it on your own because x is 82
4 0
3 years ago
Read 2 more answers
I NEED HELP ASAP!!!!!
STALIN [3.7K]

Answer: 24 C is your answer

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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