In decomposition, two or more reactant combine to form one product only.
CH3CH2OH = 46.068 (molar mass)
1.50g(1 mole / 46.0680) =
0.03256 moles
Answer:
P₂ = 1.05 atm
Explanation:
Given data:
Initial temperature = 24.0 °C (24+273 = 297 K)
Initial pressure = 0.900 atm
Final pressure = ?
Final temperature = 75 °C (75 + 273 =348 K)
Volume = constant
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
0.900 atm / 297 K = P₂/348 K
P₂ = 0.900 atm × 348 K / 297 K
P₂ = 313.2 atm. K /297 K
P₂ = 1.05 atm
Answer:
Explanation:
Hello,
This types of reactions are likely to be carried out in gaseous phase as it is easier to induce reactions, therefore, for us to compute the change in the enthalpy of this reaction we should write the formation enthalpy of gaseous methanol, hydrogen chloride, methyl chloride and water as -205.1, -92.3, -83.68 and -241.8 kJ/mol respectively. Then, the reaction enthalpy for this reaction is:
Which accounts for an exothermic chemical reaction.
Regards.
