Here the factor that Elle is controlling is the temperature. So temperature here is the independent variable and the dependent variable is the rate of evaporation of water. Independent variable is controlled during the experiment setup and the outcome of the dependent variable depends on the independent variable.

5 0

3 years ago

Rate how successful you were at using Active Reading skills by responding to the following statement: As i read, i paid attentio

Aleksandr-060686 [28]

It is possible to rate your active reading skills either by using a number is a specific rate or by using a word that qualifies your performance.

<h3>What are active reading skills?</h3>

Active reading skills are a set of skills that help you read actively; this means skills to effectively read a text and understand it.

<h3>How to rate your reading skills?</h3>

In this case, you are asked to rate your ability to pay attention to your understanding, thoughts, and questions while reading. To do this you can:

Rate using numbers:

Select a specific scale rating such as 1 to 5 or 1 10.
Analyze honestly if you used this ability while reading the text.
Give yourself a number. For example, if you apply this skill only sometimes while reading you can rate yourself 5 out of 10.

Rate using words:

Select the types of words that you will use, the most common ones are frequency words such as always, sometimes, and never.
Analyze honestly your performance.
Find the word that best fits it.

Learn more about rate in: brainly.com/question/2278897

8 0

2 years ago

A 50.00 g sample of an unknown metal is heated to 45.00°C. It is then placed in a coffee-cup calorimeter filled with water. The

V125BC [204]

Taking into account the definition of calorimetry, the specific heat of metal is 0.165 $\frac{cal}{gC}$ .

<h3>Definition of calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where:

Q is the heat exchanged by a body of mass m.
C is the specific heat substance.
ΔT is the temperature variation.

<h3>Specific heat capacity of the metal</h3>

In this case, you know:

For metal:

Mass of metal = 50 g
Initial temperature of metal= 45 °C
Final temperature of metal= 11.08 ºC
Specific heat of metal= ?

For water:

Mass of water = 250 g
Initial temperature of water= 10 ºC
Final temperature of water= 11.08 ºC
Specific heat of water = 1.035 $\frac{cal}{gC}$

Replacing in the expression to calculate heat exchanges:

For metal: Qmetal= Specific heat of metal× 50 g× (11.08 C - 45 C)

For water: Qwater= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

If two isolated bodies or systems exchange energy in the form of heat, the quantity received by one of them is equal to the quantity transferred by the other body. That is, the total energy exchanged remains constant, it is conserved.

Then, the heat that the gold gives up will be equal to the heat that the water receives. Therefore:

- Qmetal = + Qwater

- Specific heat of metal× 50 g× (11.08 C - 45 C)= 1.035 $\frac{cal}{gC}$ × 250 g× (11.08 C - 10 C)

Solving:

- Specific heat of metal× 50 g× (-33.92 C)= 1.035 $\frac{cal}{gC}$ × 250 g× 1.08 C

Specific heat of metal× 1696 g×C= 279.45 cal

Specific heat of metal= $\frac{279.45 cal}{1696 gC}$