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PtichkaEL [24]
3 years ago
15

HELPPP PLS BESTIES A pattern of stars that has been named is called a constellation. One winter evening, Jason found the star ca

lled Sirius in the constellation called Canis Major.
If Jason came outside again a few hours later, what would the stars in Canis Major look like?
A. The pattern would be smaller because the stars moved closer together.
B. The pattern would change because each star would have moved in a different direction.
C. The pattern of stars would appear to be in the same place in the sky.
D. The pattern of stars would appear to have moved together across the sky.
Physics
1 answer:
Damm [24]3 years ago
5 0

Answer:

D) Since the stars would move from East to West just as the Sun and Moon do.

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M/s^2 is the correct answer
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The texture of obsidian is best described as glassy.Why does obsidian contain few or no mineral grains? by the way I put it unde
Brrunno [24]

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3 years ago
Sheila weighs 60 kg and is riding a bike. Her momentum on the bike is 340 kg • m/s. The bike hits a rock, which stops it complet
Vikki [24]

Answer:

v₂ = 5.7 m/s

Explanation:

We will apply the law of conservation of momentum here:

Total\ Initial\ Momentum = m_{1}v_{1} + m_{2}v_{2}\\

where,

Total Initial Momentum = 340 kg.m/s

m₁ = mass of bike

v₁ = final speed of bike = 0 m/s

m₂ = mass of Sheila = 60 kg

v₂ = final speed of Sheila = ?

Therefore,

340\ kg.m/s = m_{1}(0\ m/s) + (60\ kg)v_{2}\\v_{2} = \frac{340\ kg.m/s}{60\ kg}\\\\

<u>v₂ = 5.7 m/s </u>

6 0
3 years ago
The presence of which phenomenon proved the predictability of the big bang theory?
Law Incorporation [45]
The measurement of the expansion of the universe was what gave rise to the big bang theory and it's predictions. 
7 0
3 years ago
Read 2 more answers
Enzyme reaction and deactivation Lipase is being investigated as an additive to laundry detergent for removal of stains from fab
natita [175]

Answer:

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

Explanation:given values

Half life of lipase t_1/2 = 8 min x 60s/min = 480 s

Rate constant for first order reaction

k_d = 0.6932/480 = 1.44 x 10^-3 s-1

Initial fat concentration S_0 = 45 mol/m3 = 45 mmol/L

rate of hydrolysis Vm0 = 0.07 mmol/L/s

Conversion X = 0.80

Final concentration S = S_0(1-X) = 45 (1-0.80) = 9 mol/m3

K_m = 5mmol/L

time take is given by

t= -\frac{1}{K_d}ln[1-\frac{K_d}{V_m_0}(k_mln\frac{s_0}{s}+(s_0-s))]

all values are given and putting these value we get

t=1642.83 secs

which is equal to

t= 27.38 mins [this the time taken by the enzyme to hydrolyse 80% of the fat present]

5 0
3 years ago
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