Ask question

Ask question

All categories

3 years ago

15

HELPPP PLS BESTIES A pattern of stars that has been named is called a constellation. One winter evening, Jason found the star ca

lled Sirius in the constellation called Canis Major.
If Jason came outside again a few hours later, what would the stars in Canis Major look like?
A. The pattern would be smaller because the stars moved closer together.
B. The pattern would change because each star would have moved in a different direction.
C. The pattern of stars would appear to be in the same place in the sky.
D. The pattern of stars would appear to have moved together across the sky.

1 answer:

Damm [24]3 years ago

5 0

Answer:

D) Since the stars would move from East to West just as the Sun and Moon do.

You might be interested in

An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7

Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I= $\frac{P_{avg}}{A}$

I= $\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}$

I= $7.296\times 10^{-6} W/m^2$

Amplitude of electric field at receiver end

$E_{max}=\sqrt{2I\mu _0c}$

Amplitude of induced emf

= $E_{max}d$

= $\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75$

= $17.591\times 10^{-2}=0.1759 v$

7 0

3 years ago

Explain how heat (thermal energy) can change the motion (kinetic energy) of the particles in objects.

Vika [28.1K]

Answer:

Adding heat makes the particles move faster so the particles have more kinetic energy when more thermal energy is added

Explanation:

4 0

3 years ago

If an object is not accelerating what can you determine about the sum of all the forces on the object

xxTIMURxx [149]

If object is not accelerating, the sum of all forces on the object will be equal to ZERO...

8 0

3 years ago

Two planets P1 and P2 orbit around a star S in circular orbits with speeds v1 = 40.2 km/s, and v2 = 56.0 km/s respectively. If t

Readme [11.4K]

Answer: $3.66(10)^{33}kg$

Explanation:

We are told both planets describe a circular orbit around the star S. So, let's approach this problem begining with the angular velocity $\omega$ of the planet P1 with a period $T=750years=2.36(10)^{10}s$ :

$\omega=\frac{2\pi}{T}=\frac{V_{1}}{R}$ (1)

Where:

$V_{1}=40.2km/s=40200m/s$ is the velocity of planet P1

$R$ is the radius of the orbit of planet P1

Finding $R$ :

$R=\frac{V_{1}}{2\pi}T$ (2)

$R=\frac{40200m/s}{2\pi}2.36(10)^{10}s$ (3)

$R=1.5132(10)^{14}m$ (4)

On the other hand, we know the gravitational force $F$ between the star S with mass $M$ and the planet P1 with mass $m$ is:

$F=G\frac{Mm}{R^{2}}$ (5)

Where $G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

In addition, the centripetal force $F_{c}$ exerted on the planet is:

$F_{c}=\frac{m{V_{1}}^{2}}{R^{2}}$ (6)

Assuming this system is in equilibrium:

$F=F_{c}$ (7)

Substituting (5) and (6) in (7):

$G\frac{Mm}{R^{2}}=\frac{m{V_{1}}^{2}}{R^{2}}$ (8)

Finding $M$ :

$M=\frac{V^{2}R}{G}$ (9)

$M=\frac{(40200m/s)^{2}(1.5132(10)^{14}m)}{6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}}$ (10)

Finally:

$M=3.66(10)^{33}kg$ (11) This is the mass of the star S

4 0

3 years ago

I need help on number 6 pls due today

Natalija [7]

Explanation:

Graph A matches description 4 because the car is coming back.

Graph B matches description 3 because the speed of the car is decreasing.

Graph C matches the description 2 because the car is traveling at a constant rate.

Graph D matches the description 1 because the car is stopped.

3 0

2 years ago