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konstantin123 [22]
4 years ago
7

What unit of measure would you use for mass?

Physics
1 answer:
creativ13 [48]4 years ago
6 0

grams, pounds, kilos, etc

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What is the wavelength of this wave
zhannawk [14.2K]

\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}

Actually Welcome to the Concept of the Waves.

Wavelength is the distance between two consecutive crest or trough.

hence, here the distance is 10cm

So the wavelength is 10cm

===> 10 cm

7 0
3 years ago
What is there for astronomical evidence of the light spectra?
Romashka-Z-Leto [24]

Answer:

From spectral lines astronomers can determine not only the element, but the temperature and density of that element in the star. The spectral line also can tell us about any magnetic field of the star. The width of the line can tell us how fast the material is moving. We can learn about winds in stars from this.

Explanation:

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Will give brainlist!! Please help!!
kupik [55]

Answer:

microwave, visible light, and radio waves.

Explanation:

6 0
4 years ago
An electric slot car has a coil with 100 turns of wire. These loops have a current of 0.1 A and cover an area of 0.1 cm2. If the
Marrrta [24]

Answer:

The torque will be felt by the coil is zero

Explanation:

The torque is:

\tau =\mu B=\mu Bsin\theta

Where

μ is the magnetic moment = N * I * A, where N is the number of turns, I is the current and A is the area

A = 0.1 cm² = 1x10⁻⁵m²

\mu =100*0.1*1x10^{-5} =1x10^{-4} Am^{2}

If the angle between the area and the magnetic field is 0 (are in parallel), then:

\tau =1x10^{-4} *1*sin0=0Nm

3 0
3 years ago
Two balloons (m = 0.012 kg) are separated by a distance of d = 15 m. They are released from rest and observed to have an instant
Evgesh-ka [11]

Answer:

1.492*10^14 electrons

Explanation:

Since we know the mass of each balloon and the acceleration, let’s use the following equation to determine the total force of attraction for each balloon.

F = m * a = 0.012 * 1.9 = 0.0228 N

Gravitational forces are negligible

Charge force = 9 * 10^9 * q * q ÷ 225

= 9 * 10^9 * q^2 ÷ 225 = 0.0228

q^2 = 5.13 ÷ 9 * 10^9

q = 2.387 *10^-5

This is approximately 2.387 *10^-5 coulomb of charge. The charge of one electron is 1.6 * 10^-19 C

To determine the number of electrons, divide the charge by this number.

N =2.387 *10^-5  ÷ 1.6 * 10^-19 = 1.492*10^14 electrons

3 0
3 years ago
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