The game starts with the serve on the left side of the court.<br> O<br> True<br> O<br> False

What is the best explanation for why a magnet is different from a regular piece of metal?

arlik [135]

Answer:

in a magnet there is a magnetic field that draws ever mental to it

5 0

2 years ago

At a given location from a source charge, the electric field______________.a. strength is dependent on the source charge and the

noname [10]

Answer:

b. The electric field points away from the source charge, if the source charge is positive

d. The electric field points toward the source charge, if the source charge is negative.

Explanation:

A positive source charge would create an electric field that would exert a repulsive effect upon a positive test charge. Thus, the electric field vector would always be directed away from positively charged objects. On the other hand, a positive test charge would be attracted to a negative source charge. Therefore, electric field vectors are always directed towards negatively charged object.

Also electric field strength depends only on test charge

The correct options include b and d

The electric field points away from the source charge, if the source charge is positive.

Also, the electric field points toward the source charge, if the source charge is negative.

3 0

2 years ago

Two long, parallel wires carry unequal currents in the same direction. The ratio of the currents is 3 to 1. The magnitude of the

astraxan [27]

Answer:

3A is the larger of the two currents.

Explanation:

Let the currents in the two wires be I₁ and I₂

given:

Magnitude of the electric field, B = 4.0μT = 4.0×10⁻⁶T

Distance, R = 10cm = 0.1m

Ratio of the current = I₁ : I₂ = 3 : 1

Now, the magnitude of a magnetic field at a distance 'R' due to the current 'I' is given as

$B = \frac{\mu_oI}{2\pi R}$

Where $\mu_o$ is the magnitude constant = 4π×10⁻⁷ H/m

Thus, the magnitude of a magnetic field due to I₁ will be

$B_1 = \frac{\mu_oI_1}{2\pi R}$

$B_2 = \frac{\mu_oI_2}{2\pi R}$

given,

B = B₁ - B₂ (since both the currents are in the same direction and parallel)

substituting the values of B, B₁ and B₂

we get

4.0×10⁻⁶T = $\frac{\mu_oI_1}{2\pi R}$ - $\frac{\mu_oI_2}{2\pi R}$

or

4.0×10⁻⁶T = $\frac{\mu_o}{2\pi R}\times (I_1-I_2 )$

also

$\frac{I_1}{I_2} = \frac{3}{1}$

⇒ $I_1 = 3\times I_2$

substituting the values in the above equation we get

4.0×10⁻⁶T = $\frac{4\pi\times 10^{-7}}{2\pi 0.1}\times (3 I_2-I_2)$

⇒ $I_2 = 1A$

also

$I_1 = 3\times I_2$

⇒ $I_1 = 3\times 1A$

⇒ $I_1 = 3A$

Hence, the larger of the two currents is 3A

3 0

3 years ago

7) Sound waves travel with a nominal speed of 340 m/s. Calculate the wavelengths of the following musical notes:

Oksana_A [137]

The wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.

Answer:

Explanation:

Since, wavelength, frequency and speed of sound waves are related to each other, we can determine a single parameter with the help of other two parameters. So in this case, the frequency of different notes are given along with their common speed. So as the frequency is inversely proportional to the wavelength then in this case, the wavelength of the notes will be maximum for C1 and minimum for 3951.1 Hz.

Wavelength = Speed / Frequency

Wavelength for C1 note = 340 / 32.7 =10.40 m

Similarly, the wavelength for A6 note = 340/1760=0.193 m

And, the wavelength for B7 note = 340/3951.1 = 0.086 m

So, the wavelength for C1 note is 10.40 m, for A6 note is 0.193 m and for B7 note 0.086 m.

6 0

3 years ago

is to the east. (i) Automobile A travels 50 km due east. (ii) Automobile B travels 50 km due west. (iii) Automobile C travels 60

kenny6666 [7]

Complete Question:

Each of the following trips lasts exactly one hour. The positive direction is to the east.

(i) Automobile A travels 50 km due east. (ii) Automobile B travels 50 km due west. (iii) Automobile C travels 60 km due east, then turns around and travels 10 km due west. (iv) Automobile D travels 70 km due east. (v) Automobile E travels 20 km due west, then turns around and travels 20 km due east. (a) Rank the five trips in order of average x-velocity from most positive to most negative. (b) Which trips, if any, have the same average x-velocity? (c) For which trip, if any, is the average x-velocity equal to zero?

Answer:

a) 1. (iv) 2.) (i) and (iii). 3. (v) 4.(ii)

Explanation:

By definition, the average velocity, can be expressed as the total displacement (the difference between the final and initial position), divided by the time interval during which we define the displacement.

We can put these words in an equation format as follows:

$vavg,x = \frac{xf-xo}{t-to}$

If we choose x₀ = 0 and t₀ = 0, the average velocity is just the final position over one hour.

The final positions, in the five trips, are as follows:

(i) = +50 Km (2nd)

(ii) = -50 Km (4th)

(iii) + 60 Km -10 Km = + 50 km (2nd)

(iv) = + 70 km (1st)

(v) = -20 km + 20 Km = 0 (3rd)

b) As stated above, the trips (i) and (iii) have the same average x-velocity.

c) As stated above, in trip (v) as the total displacement is 0, average -velocity is 0 also.

5 0

3 years ago

The game starts with the serve on the left side of the court. O True O False