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blagie [28]
3 years ago
7

Solve the system of linear equations by elimination. x+4y=6 −x−2y=−4

Mathematics
1 answer:
REY [17]3 years ago
3 0

Answer:

(x , y) = (2 , 1)

Step-by-step explanation:

// Solve equation [1] for the variable x

[1] x = -4y + 6

// Plug this in for variable x in equation [2]

[2] -(-4y+6) - 2y = -4

[2] 2y = 2

// Solve equation [2] for the variable y

[2] 2y = 2

[2] y = 1

// By now we know this much :

x = -4y+6

y = 1

// Use the y value to solve for x

x = -4(1)+6 = 2

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KATRIN_1 [288]

Answer:

Purplemath

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8 0
2 years ago
Dude is making 12 pounds of nut mixture with macadamia nuts and almonds. Macadamia nuts cost $9 per pound and almonds cost $5.25
pshichka [43]

Number of pounds of macadamia nuts is 8 pounds and number of pounds of almonds is 4 pounds.

<u>Step-by-step explanation:</u>

Step 1:

Given total pounds of mixture = 12 pounds, cost of macadamia nuts per pound = $9, cost of almonds per pound = $5.25, total cost of mixture per pound = $7.75.

Let number of pounds of macadamia nuts be x and number of pounds of almonds be 12-x.

Step 2:

Form an equation using the above information.

⇒ 9x + 5.25 (12-x) = 12 × 7.75

⇒ 9x + 63 - 5.25x = 93

⇒ 9x - 5.25x = 30

⇒ 3.75x = 30

⇒ x = 8

Number of macadamia nuts is 8 pounds.

Step 3:

Calculate number pounds of almonds

⇒ Number of pounds of almonds = 12 - x = 4 pounds.

5 0
3 years ago
Find the linear approximation of the function g(x) = 3 root 1 + x at a = 0. g(x). Use it to approximate the numbers 3 root 0.95
Virty [35]

Answer:

L(x)=1+\dfrac{1}{3}x

\sqrt[3]{0.95} \approx 0.9833

\sqrt[3]{1.1} \approx 1.0333

Step-by-step explanation:

Given the function: g(x)=\sqrt[3]{1+x}

We are to determine the linear approximation of the function g(x) at a = 0.

Linear Approximating Polynomial,L(x)=f(a)+f'(a)(x-a)

a=0

g(0)=\sqrt[3]{1+0}=1

g'(x)=\frac{1}{3}(1+x)^{-2/3} \\g'(0)=\frac{1}{3}(1+0)^{-2/3}=\frac{1}{3}

Therefore:

L(x)=1+\frac{1}{3}(x-0)\\\\$The linear approximating polynomial of g(x) is:$\\\\L(x)=1+\dfrac{1}{3}x

(b)\sqrt[3]{0.95}= \sqrt[3]{1-0.05}

When x = - 0.05

L(-0.05)=1+\dfrac{1}{3}(-0.05)=0.9833

\sqrt[3]{0.95} \approx 0.9833

(c)

(b)\sqrt[3]{1.1}= \sqrt[3]{1+0.1}

When x = 0.1

L(1.1)=1+\dfrac{1}{3}(0.1)=1.0333

\sqrt[3]{1.1} \approx 1.0333

7 0
3 years ago
Can you help me please??
dusya [7]

Answer:

y = \frac{4}{5}x+\frac{54}{5}

Step-by-step explanation:

Equation of a line has been given as,

y=\frac{4}{5}x+\frac{3}{5}

Here, slope of the line = \frac{4}{5}

y-intercept = \frac{3}{5}

"If the two lines are parallel, there slopes will be equal"

By this property slope of the parallel line to the given line will be equal.

Therefore, slope 'm' = \frac{4}{5}

Since, slope intercept form of a line is,

y = mx + b

Therefore, equation of the parallel line will be,

y = \frac{4}{5}x+b

Since, this line passes through a point (-6, 6),

6 = \frac{4}{5}(-6)+b

6 = -\frac{24}{5}+b

b = 6+\frac{24}{5}

b = \frac{30+24}{5}

b = \frac{54}{5}

Equation of the parallel line will be,

y = \frac{4}{5}x+\frac{54}{5}

4 0
3 years ago
Which of the following is the solution to the system of equations shown below?
antiseptic1488 [7]

Answer:

x = -2, x = 1

Step-by-step explanation:

mark as brainliest it is right

3 0
3 years ago
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