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2 years ago

What is the area of the triangle? (giving brainliest if right)

Mathematics

1 answer:

wel2 years ago

3 0

Answer:

Step-by-step explanation:

b = base

h = height

Area of triangle = 1/2 * b*h

1/2 * 8 * 10

= 40 units^2

Hope it helps

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On a hiking trip, Melissa notes that she hikes about 16 kilometers every 2.5 hours. If she continues at this rate, about how man

svp [43]

Answer:

so if she hike 12 km every 4 hours, how many km could she hike in 6 hours.

first u have to find the equation. 12 km=4hours

? =6hours

and then you have to multiply 12 km by 6 hours and divide the results by 4 which is 12×6÷4. the final answer will be 18 kilometers.

Step-by-step explanation:

Sorry if its wrong

5 0

2 years ago

If i=√-1 , what is i^2 equal to ?

Alja [10]

Answer:

-1

Step-by-step explanation:

If i = √-1, then i^2 = -1.

5 0

3 years ago

6⋅[(32−8)÷4+2] What is the answer to this expession?

Nimfa-mama [501]

Answer:

Step-by-step explanation:

=6*[24/4+2]

=6*[6+2]

=6*8

=48

4 0

3 years ago

Construct 3 linear equation starting with qiven solution z = 1/3

Andreyy89

Answer:

(a) $9z+2=5$

(b) $21z-11=-4$

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

Equation 1

$z=\frac{1}{3}$

Multiply both sides by 9

$9z=\frac{1}{3}\times 9\\9z=3$

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: $9z+2=5$

Equation 2

$z=\frac{1}{3}$

Multiply both sides by 21

$21z=\frac{1}{3}\times 21\\21z=7$

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: $21z-11=-4$

Equation 3

$z=\frac{1}{3}$

Multiply both sides by 6

$6z=\frac{1}{3}\times 6\\6z=2$

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: $4z=2-2z$

4 0

3 years ago

Find the distance between (-2, 8) and (11, 2). Round to the nearest hundredth.

MakcuM [25]

Answer:

14.32

Step-by-step explanation:

We can find the distance using the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

We then substitute (-2,8) as $(x_1,y_1)$ and (11,2) as $(x_2,y_2)$ .

$d=\sqrt{(11--2)^2+(2-8)^2} \\d=\sqrt{(13)^2+(-6)^2} \\d=\sqrt{169+36}\\d=\sqrt{205}=14.32$

6 0

3 years ago