Volume of a quadrangular pyramid=(1/3)bh
b=base
h=height
b=area of the base=area of a square=8.4 ft * 8.4 ft=70.56 ft²
Pythagoras theorem:
hypotenuse²=leg₁² + leg₂²
data:
hypotenuse=9.6 ft
leg₁=height=h
leg₂=8.4 ft /2=4.2 ft
(9.6 ft)²= h² + (4.2 ft)²
92.16 ft²=h²+17.64 ft²
h²=92.16 ft²-17.64 ft²
h²=74.52 ft²
h=√(74.52 ft²)=8.63 ft.
Volume of this quadrangular pyramid=(1/3)(70.56 ft²)(8.63 ft)=202.9 ft³≈202.3 ft³
Answer: ≈202.3 ft³
Slope = change in y / change in x
slope = (9 - -5) / ( 6-0)
Slope = 14/6
Divide by 2
Slope = 7/3
Answer: B. 7/3
Answer:
Whatever number added to 0 remains the same.
Step-by-step explanation:
When you add a number to 0, the number itself doesn't change at all because there isn't anything in 0. So any number that is added to 0 doesn't change at all.
Hello!
First the left side:
5 ⋅ 5= 25
Now the right:
5 ⋅5=25 25⋅5 is 125
Now we add the two together and we get 150.
I hope it helps!
