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Eva8 [605]
3 years ago
14

PLEASE HELP ME!!! I WILL GIVE YOU 15 POINTS​

Mathematics
2 answers:
Leni [432]3 years ago
8 0

Answer:

gl with that

Step-by-step explanation:

Daniel [21]3 years ago
7 0

Answer:

the correct answer is option B. x=2, y=0

hope it helps you

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Answer:

22 degree ............,........

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Can some please help me with this problem It's a little confusing to me.
Nat2105 [25]
Diameter = 10.0002 inches, or 10 inches since were rounding to the nearest whole number.
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Read 2 more answers
4 x 5 - (2² - 2) =? <br> (18 ÷ 3) + (3² - 7) =?
OverLord2011 [107]
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Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati
Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that \mu = 5.8, \sigma = 0.8

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

Z = \frac{X - \mu}{\sigma}

-1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = -1.74*0.8

X = 4.41

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

Z = \frac{X - \mu}{\sigma}

1.74 = \frac{X - 5.8}{0.8}

X - 5.8 = 1.74*0.8

X = 7.19

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0
3 years ago
Graph this please any math expert please thank you
Pani-rosa [81]

Answer:

we cant see the picture but if i could i would have solved it

Step-by-step explanation:

we cant see the picture n

3 0
3 years ago
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