Answer:
8.27°
Explanation:
To angle difference will be determined by the difference in the displacement of the springs, produced by the weight of the center of mass of the rod.
![d=y_1-y_2=\frac{F_1}{k_1}-\frac{F_2}{k_2}=\frac{0.5mg}{31N/m}-\frac{0.5mg}{63N/m}\\\\d=0.5(1.6kg)(9.8m/s^2)[\frac{1}{31N/m}-\frac{1}{63N/m}]=0.128m](https://tex.z-dn.net/?f=d%3Dy_1-y_2%3D%5Cfrac%7BF_1%7D%7Bk_1%7D-%5Cfrac%7BF_2%7D%7Bk_2%7D%3D%5Cfrac%7B0.5mg%7D%7B31N%2Fm%7D-%5Cfrac%7B0.5mg%7D%7B63N%2Fm%7D%5C%5C%5C%5Cd%3D0.5%281.6kg%29%289.8m%2Fs%5E2%29%5B%5Cfrac%7B1%7D%7B31N%2Fm%7D-%5Cfrac%7B1%7D%7B63N%2Fm%7D%5D%3D0.128m)
by a simple trigonometric relation you obtain that the angle:
hence, the angle between the rod and the horizontal is 8.27°
Answer:
A) The green cars's velocity has the same magnitude as the blue car's velocity.
B) the difference about their velocity is the direction of the velocity which is 180° in the opposite directions.
Explanation:
Velocity is a vector quantity that has both magnitude and direction. The magnitude shows the size, and the direction shows the path the motion takes.
Both cars have the same magnitude but different directions. The difference in their direction is at a 180°angle.
Answer:
A. Workdone by helium, W = -1.829KJ
B. Internal energy, DE = 25.271KJ
Explanation:
Workdone can be defined as the force moving through a distance. For a gaseous system, when the volume of the gas expands, the system is losing energy. Therefore,
W = -P*DV
Where P is the pressure in pascal
DV is the change in volume in m3
DV = Vfinal - Vinitial
= 23.70 - 5.30
= 18.4L
W = -(0.981 * 18.4)
= -18.0504L.atm
Converting L.atm to joule,
= -18.0504 * 101.325
= -1828.97J
= -1.829KJ
If the system loses heat, Q the rection occurring is Exothermic.
Heat is the transfer of energy from one system to another.
Q = mcDT
Where m is the mass of the system
C is the specific heat capacity
Q = 27.20KJ
Internal energy is the summation of the heat supplied to a system and the workdone by the system
DE = Q + W
DE = 27.10 + (-1.829)
= 25.27KJ
It is the first on differences in water temperature.
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