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Arada [10]
3 years ago
9

PLEASE HELP!! PHYSICS QUIZ!

Physics
2 answers:
diamong [38]3 years ago
5 0

1.

Answer: True

Explanation: A projectile is launched at certain angle with the horizontal. Hence, its equation of motion can be described using vertical and horizontal components. Therefore, the statement is true.

2.

Answer: False

Explanation:

The shape of the trajectory of a projectile is parabola. Hence, the given statement is false.

3.

Answer: A) constant

Explanation: During the course of trajectory, the horizontal component of the velocity is constant. There is no external force acting in the horizontal direction. In the vertical direction,  acceleration due to gravity acts which increases the vertical component of velocity. Hence, the correct option is A.

Dmitriy789 [7]3 years ago
4 0

1).  Technically false if you're persnickety about your words.  But this quiz wants you to say 'True'.

The projectile doesn't have vertical and horizontal components.  But if the projectile is <em>moving</em>, then its displacement, velocity, and acceleration can have vertical and horizontal components.

2).  This one's <em>false.</em>  The shape of a projectile's trajectory is a parabola. (Unless the projectile is moving fast enough to be in a stable orbit.  THEN its path is an ellipse.)

3). During the time the projectile is flying, the horizontal component of its velocity is <em>constant</em> IF THERE'S NO AIR RESISTANCE.

If there IS air resistance, then the horizontal component of velocity is decreasing.

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Is the energy of a wave is calculated by squaring the frequency of the wave?
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3 years ago
A launched hopper reach to 1.20 m maximum height. How much is it’s launch velocity?
garri49 [273]

The launch velocity is 4.8 m/s

Explanation:

We can solve this problem by applying the law of conservation of energy. In fact, the mechanical energy of the hopper (equal to the sum of the potential energy + the kinetic energy) is conserved. So we can write:

U_i +K_i = U_f + K_f

where:

U_i is the initial potential energy, at the bottom

K_i is the initial kinetic energy, at the bottom

U_f is the final potential energy, at the top

K_f is the final kinetic energy, at the top

We can rewrite the equation as:

mgh_i + \frac{1}{2}mu^2 = mgh_f + \frac{1}{2}mv^2

where:

m is the mass of the hopper

g=9.8 m/s^2 is the acceleration of gravity

h_i = 0 is the initial height

u is the launch speed of the hopper

h_f = 1.20 m is the maximum altitude reached by the hopper

v = 0 is the final speed (which is zero when the hopper reaches the maximum height)

Solving the equation for u, we find the launch speed of the hopper:

u=\sqrt{2gh_g}=\sqrt{2(9.8)(1.20)}=4.8 m/s

Learn more about kinetic energy and potential energy:

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A simple pendulum consisting of a bob of mass m attached to a string of length L swings with a period T. If the pendulum is take
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To solve this problem we will use the definition of the period in a simple pendulum, which warns that it is dependent on its length and gravity as follows:

T =2\pi \sqrt{\frac{L}{g}}

Here,

L = Length

g = Acceleration due to gravity

We can realize that 2 \pi is a constant so it is proportional to the square root of its length over its gravity,

T \propto \sqrt{\frac{L}{g}}

Since the body is in constant free fall, that is, a point where gravity tends to be zero:

g \rightarrow 0 \Rightarrow T \rightarrow \infty

The value of the period will tend to infinity. This indicates that the pendulum will no longer oscillate because both the pendulum and the point to which it is attached are in free fall.

5 0
3 years ago
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