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2 years ago

PLEASE HELP!! PHYSICS QUIZ!

Physics

2 answers:

diamong [38]2 years ago

5 0

Answer: True

Explanation: A projectile is launched at certain angle with the horizontal. Hence, its equation of motion can be described using vertical and horizontal components. Therefore, the statement is true.

Answer: False

Explanation:

The shape of the trajectory of a projectile is parabola. Hence, the given statement is false.

Answer: A) constant

Explanation: During the course of trajectory, the horizontal component of the velocity is constant. There is no external force acting in the horizontal direction. In the vertical direction, acceleration due to gravity acts which increases the vertical component of velocity. Hence, the correct option is A.

Dmitriy789 [7]2 years ago

4 0

1). Technically false if you're persnickety about your words. But this quiz wants you to say 'True'.

The projectile doesn't have vertical and horizontal components. But if the projectile is moving, then its displacement, velocity, and acceleration can have vertical and horizontal components.

2). This one's false. The shape of a projectile's trajectory is a parabola. (Unless the projectile is moving fast enough to be in a stable orbit. THEN its path is an ellipse.)

3). During the time the projectile is flying, the horizontal component of its velocity is constant IF THERE'S NO AIR RESISTANCE.

If there IS air resistance, then the horizontal component of velocity is decreasing.

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Acceleration always involves a change in

Scrat [10]

Velocity. Since velocity consists of a speed and a direction, acceleration is a change in speed, or direction, or both.

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A child is riding a merry-go-round that is turning at 7.18 rpm. if the child is standing 4.65 m from the center of the merry-go-

Alisiya [41]

First we need to convert the angular speed from rpm to rad/s. Keeping in mind that
$1 rev= 2 \pi rad$
$1 min = 60 s$
the angular speed is
$\omega = 7.18 \frac{rev}{min} \cdot \frac{2 \pi}{60} = 0.75 rad/s$

And so now we can calculate the tangential speed of the child, which is the angular speed times the distance of the child from the center of the motion:
$v= \omega r = (0.75 rad/s)(4.65 m)=3.50 m/s$

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2 years ago

A circuit can only light up a lightbulb if there is a ______ path for electricity to travel from one end of the energy source to

Dmitry_Shevchenko [17]

Answer:

Continuous

Explanation:

A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.

4 0

2 years ago

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Can some one please answers number 4

Maru [420]

I think it is the core and outer core.
hope this helped.

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2 years ago

Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force

gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

$F=k\frac{q_1q_2}{r^2}$

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

$F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}$

$F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N$

Ft=0N

Hope this helps!!

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2 years ago

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