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ElenaW [278]
3 years ago
7

What is the sum of the two expressions? (2/5 x + 3) + (1/5 x - 1)

Mathematics
2 answers:
Ede4ka [16]3 years ago
6 0

Answer: \frac{3}{5}x + 2

Step-by-step explanation:

\frac{2}{5}x + 3 + \frac{1}{5}x - 1

add like terms together

\frac{2}{5}x + \frac{1}{5}x + 3 -1\\\frac{3}{5}x + 2

marshall27 [118]3 years ago
3 0

Answer:

2x/5 + 3 + x/5

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Read 2 more answers
Given f (x)=2x-5x-3 and g (x)=2x^2+x what is (f/g)(x)<br>​
Rufina [12.5K]

ANSWER

( \frac{f}{g} )(x ) =   \frac{x - 3}{x}  \: where \:  \: x \ne0, -  \frac{1}{2}

EXPLANATION

Given:

f(x) = 2 {x}^{2}  - 5x - 3

and

g(x) = 2 {x}^{2}  + x

Then,

( \frac{f}{g} )(x ) =  \frac{f(x)}{g(x)}

Substitute the given functions;

( \frac{f}{g} )(x )  =  \frac{2 {x}^{2} - 5x - 3}{2 {x}^{2}  + x}

Factor

( \frac{f}{g} )(x ) =  \frac{2 {x}^{2} - 6x + x - 3 }{x(2x + 1)}

( \frac{f}{g} )(x ) =   \frac{2x(x - 3) +1 (x - 3)}{x(2x + 1)}

( \frac{f}{g} )(x ) =   \frac{(2x + 1)(x - 3) }{x(2x + 1)}

Cancel the common factors.

( \frac{f}{g} )(x ) =   \frac{x - 3}{x}  \: where \:  \: x \ne0, -  \frac{1}{2}

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