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denis23 [38]
3 years ago
5

Assume that a resistor is connected between the 150 V terminal and the common terminal. The voltmeter is then connected to an un

known voltage using the common terminal and the 300 V terminal. The voltmeter reads 288 V.What is the unknown voltage
Physics
1 answer:
Lena [83]3 years ago
7 0

Answer: 316.8V

Explanation:

given data:

metre moving current = 0.96mA

meters voltage = 288V

or  0.96*300V = 288V

<u><em>Solution:</em></u>

<u><em /></u>v1 = (0.96mA*150)<u><em /></u>

<u><em /></u>= 144V<u><em /></u>

<u><em /></u>

i1 = \frac{144v}{750}

= 0.192mA

i2 = imovement + i1

i2= 0.96mA+0.192mA

= 1.152mA

Vmeasured = 144V+(150)(1.152mA)

=316.8V

the unknown voltage is 316.8V

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3 years ago
you find out that it takes 2 sec. for the swing to complete one cycle. what is the swing`s period and frequency?
Gnesinka [82]

The time it takes "to complete one cycle" is a perfect definition for <em>period</em>.
So the <em>2 sec</em> that you measured is the swing's period.

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Which of the following is an example of a chemical change?
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THE ANSWER IS

D. A gas when vinegar and baking soda are mixed

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5 0
3 years ago
Read 2 more answers
A 80 kg block starts from rest at the top of a 15m frictionless ramp. The block slides down the frictionless ramp onto a rough h
Nadusha1986 [10]

Answer:

W(fric) = -12000 J

Explanation:

Given that

mass ,m= 80 kg

Initial speed ,u= 0 m/s

Height ,h= 15 m

Final speed ,v= 0 m/s

We know that

Work done by all the forces = Change in the kinetic energy

W_{gravity}+W_{fric}=\dfrac{1}{2}mv^2-\dfrac{1}{2}mu^2

W_{gravity}+W_{fric}=\dfrac{1}{2}m\times 0^2-\dfrac{1}{2}m\times 0^2

W_{gravity}+W_{fric}=0

W(fric)= - m g h

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W(fric) = -12000 J

negative sign indicates that force and displacement is in opposite direction.

5 0
3 years ago
A car accelerates uniformly from rest and reaches a speed of 22.0 m/s in 9.00 s. Assuming the diameter of a tire is 58.0 cm, (a)
Virty [35]

Answer:

Explanation:

Given:

Initial velocity, u = 0 m/s (at rest)

Final velocity, v = 22 m/s

Time, t = 9 s

Diameter, d = 58 cm

Radius, r = 0.29 m

Using equation of motion,

v = u + at

a = (22 - 0)/9

= 2.44 m/s^2

v^2 = u^2 + 2a × S

S = (22^2 - 0^2)/2 × 2.44

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S = r × theta

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1 rev = 360°

341.44°,

= 341.44/360

= 0.948 rev

= 0.95 rev

B.

Final angular speed, wf = v/r

= 22/0.29

= 75.86 rad/s

6 0
3 years ago
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