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ioda
3 years ago
15

What is the change in velocity of a 22-kg object that experiences a force of 15 N for

Physics
1 answer:
vagabundo [1.1K]3 years ago
3 0

Answer:

Force = mass × acceleration

Acceleration:

{ \tt{15 = (22 \times a)}} \\ { \tt{a =  \frac{15}{22}  \:  {ms}^{ - 2} }}

From first Newton's equation of motion:

{ \bf{v = u + at}}

Change = v - u:

{ \tt{v - u = (a \times t)}} \\ { \tt{v - u = ( \frac{15}{22} \times 1.2) }} \\ { \tt{v - u = 0.82 \:  {ms}^{ - 2} }}

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A student needs to travel a total of 400 miles to reach his vacation destination . if he drives at an average speed of 50 mph ho
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The fraction of the water must evaporate to remove precisely enough energy to keep the temperature constant when water at 37°c has a latent heat of vaporization of lv = 580 kcal/kg is 2.58 times 10 to the minus 3.

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5 0
1 year ago
Determine the vector perpendicular to the plane of A= 31+ 6j - 2k and B=4i-j +3k
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The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k

Let r be the vector perpendicular to A and B,

r = A * B

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B = 4i - j + 3k

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a2 = 6

a3 = - 2

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The perpendicular vector, r = 16 i - 17 j - 27 k

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