To find the horizontal distance multiple the horizontal velocity by the time. Since there is no given time it must be calculated using kinematic equation. 
Y=Yo+Voyt+1/2at^2
0=.55+0+1/2(-9.8)t^2
-.55=-4.9t^2
sqrt(.55/4.9)=t
t=0.335 seconds
Horizontal distance
=0.335s*1.2m/s
=0.402 meters
        
             
        
        
        
the axis acts against and it would be a contact force
 
        
                    
             
        
        
        
It depends on what type of solid
        
             
        
        
        
Answer:
15.7m/s
Explanation:
To solve this problem, we use the right motion equation. 
  Here, we have been given the height through which the ball drops;
  Height of drop = 14.5m - 1.9m  = 12.6m 
 The right motion equation is; 
       V²  = U² + 2gh 
V is the final velocity 
U is the initial velocity  = 0 
g is the acceleration due to gravity  = 9.8m/s²
h is the height
   Now insert the parameters and solve; 
        V² = 0² + 2 x 9.8 x 12.6 
       V²  = 246.96 
        V = √246.96  = 15.7m/s