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aleksandr82 [10.1K]
3 years ago
12

A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog

Physics
2 answers:
Nuetrik [128]3 years ago
5 0
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.
RUDIKE [14]3 years ago
4 0

The initial displacement=d1= 30 feet North

d2= -5 feet south

we take d2 as negative because we treat south direction as negative

so the net displacement= d1+d2

net displacement= -5+30

net displacement=25

so the net displacement= 25 feet North.

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A bus travels 6 km east and then 8 km south. The magnitude of the bus’s resultant displacement is ___km.
Crank

Answer:

10 km

Explanation:

You can draw your problem out. You can use the pathagoran theorem to figure it out. So 6^{2} + 8^{2} and then square root the answer which will be \sqrt{100} which equals to 10.

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What is the mass of an object if it took 270 J of work to move it 15 meters? Please help!
maxonik [38]
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5 0
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The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the
erica [24]

Answer:

0.235 nC

Explanation:

Given:

  • E = the magnitude of electric field = 8.50\ kN/C =8.50\times 10^{3}\ N/C
  • F = the magnitude of electric force on each antenna = 2.00\ \mu N =2.00\times 10^{-6}\ N
  • q = The magnitude of charge on each antenna

Since the electric field is the electric force applied on a charged body of unit charge.

\therefore E = \dfrac{F}{q}\\\Rightarrow q =\dfrac{F}{E}\\\Rightarrow q =\dfrac{2.00\times 10^{-6}\ N}{8.50\times 10^{3}\ N/C}\\\Rightarrow q =0.235\times 10^{-9}\ C\\\Rightarrow q =0.235\ nC

Hence, the value of q is 0.235 nC.

4 0
3 years ago
1. The volume of a given mass of gas is 20cm when its
Pavel [41]

Answer:

Explanation:

The way to show a cubed substance is either like this³ or like this x^3. The small three is found at the bottom toolbar at the bottom of the question space marked by the  Ω symbol.

100 mmHg

Givens

V1 = 20 cm^3

V2 = 80 cm^3

P1 = 400 mmHg

P2 = ?

Formula

V1 * P1 = V2 * P2

Solution

20 * 400 = 80 * P2              Divide by 80

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P2 = 100 mmHg

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I only know P and V and P is pressure and V is volume 
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