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aleksandr82 [10.1K]
3 years ago
12

A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog

Physics
2 answers:
Nuetrik [128]3 years ago
5 0
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.
RUDIKE [14]3 years ago
4 0

The initial displacement=d1= 30 feet North

d2= -5 feet south

we take d2 as negative because we treat south direction as negative

so the net displacement= d1+d2

net displacement= -5+30

net displacement=25

so the net displacement= 25 feet North.

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Answer:

The horizontal component of displacement is d' = 1422.7 m

Explanation:

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The angle formed with the horizontal, Ф = 5.76°

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The horizontal component of displacement is given by,

                                 d' = d cos Ф

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