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3 years ago

A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog

Physics

2 answers:

Nuetrik [128]3 years ago

5 0

To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.

RUDIKE [14]3 years ago

4 0

The initial displacement=d1= 30 feet North

d2= -5 feet south

we take d2 as negative because we treat south direction as negative

so the net displacement= d1+d2

net displacement= -5+30

net displacement=25

so the net displacement= 25 feet North.

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Explanation:

It is given that,

Wavelength of red laser light, $\lambda=632.8\ nm=632.8\times 10^{-9}\ m$

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For diffraction grating,

$d\ sin\theta=n\lambda$

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3 years ago

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E. all of the above

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