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aleksandr82 [10.1K]
4 years ago
12

A dog runs 30 feet to the north then 5 feet to the south what is the displacement of the dog

Physics
2 answers:
Nuetrik [128]4 years ago
5 0
To look for displacement, just draw a vector from your beginning stage to your last position and settle for the length of this line. So we begin by drawing a line to the north which is 30 ft, since it is north, the line is going up, then it move 5 ft to the south, so put a line going down, so we are in 25 ft, North so that would be the answer.
RUDIKE [14]4 years ago
4 0

The initial displacement=d1= 30 feet North

d2= -5 feet south

we take d2 as negative because we treat south direction as negative

so the net displacement= d1+d2

net displacement= -5+30

net displacement=25

so the net displacement= 25 feet North.

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4 years ago
A cliff diver from the top of a 100 (m) cliff. He begins his dive by jumping up with a velocity of 5 (m/s) a. How
Nutka1998 [239]

Answer:

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The time taken for the diver to reach the water from the maximum height can be calculated by using second equation of motion.

Where height h = 1.28 + 100 = 101.28 m

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t = sqrt ( 20.669)

t = 4.55s

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The time taken for him to hit the water below will be 0.256 + 4.55 = 4.81 seconds

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4 years ago
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ivanzaharov [21]

Answer:

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3 years ago
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<h2>Hey there!</h2>

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