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3 years ago

For each graph below, state wether it represents a function.

Mathematics

1 answer:

Paul [167]3 years ago

8 0

Answers:

Row 1: No, No, No

Row 2: Yes, Yes, Yes

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Explanation:

Use the vertical line test. If it is at all possible to draw a single vertical line through more than one point on the relation curve, then the relation is not a function. This is because a function is only possible when any x input leads to exactly one y output.

So that's why graphs 1,2,3 are not functions, while graphs 4,5,6 are functions.

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Charlotte is working two summer jobs, making $7 per hour washing cars and making $15 per hour clearing tables. In a given week,

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Answer:

Claire must work 4 hours cleaning tables and 5 hours washing cars to earn more than $ 90.

Since Claire is working two summer jobs, making $ 7 per hour washing cars and making $ 15 per hour clearing tables, and in a given week, she can work at most 9 total hours and must earn a minimum of $ 90, to determine one possible solution the following calculation must be performed:

15 x 9 = 135

135 - 90 = 45

45/7 = 6.42

6 x 7 + 3 x 15 = 42 + 45 = 87

5 x 7 + 4 x 15 = 35 + 60 = 95

Therefore, at a minimum, Claire must work 4 hours cleaning tables and 5 hours washing cars to earn more than $ 90.

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1 year ago

A line passes through the points (0,3), (4,1) and (6,0). Which function best represents the relationship between the two points?

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Answer:

y = - $\frac{1}{2}$ x + 3

Step-by-step explanation:

y = mx + b

m = $\frac{y_{2} -y_{1} }{x_{2} -x_{1} }$ and "b" is y-intercept with coordinates (0, b)

(0, 3) ⇒ b = 3

(4, 1), (6, 0)

m = $\frac{0-1}{6-4}$ = - $\frac{1}{2}$

y = -  $\frac{1}{2}$  x + 3

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2 years ago

Jorge said that y-values would stay the same when you reflect a preimage across the line y=5 since the y-values stay the same wh

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No because y=5 is a horizontal line on a graph, in this scenario the x-values would stay the same

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3 years ago

Lamar is writing a coordinate proof to show that a segment from the midpoint of the hypotenuse of a right triangle to the opposi

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1. N is a midpoint of the segment KL, then N has coordinates

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$A_{KMN}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2b\cdot a=ab.$

3. To find the area of △MNL, the length of the base ML is 2a and the length of the height is b. So an expression for the area of △MNL is

$A_{MNL}=\dfrac{1}{2}\cdot \text{base}\cdot \text{height}=\dfrac{1}{2}\cdot 2a\cdot b=ab.$

4. Comparing the expressions for the areas you have that the area $A_{KMN}$ is equal to the area $A_{MNL}$ . This means that the segment from the midpoint of the hypotenuse of a right triangle to the opposite vertex forms two triangles with equal areas.

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3 years ago

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