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Goryan [66]
3 years ago
10

Does anyone know he answers for 2 and 3? Need full work and explanations

Mathematics
1 answer:
torisob [31]3 years ago
7 0

Answer:

this is the answer of 2 and

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If 1/4 inch= 8 feet, how many inches would 136 feet be
Paha777 [63]
Answer: 4.25 inches of 4 and 1/4 inches.

Explanation: Use the information already given to you 1/4 of a inch = 8 ft. So if you have 4/4 of an inch that would equal one inch and one whole inch would equals 32 ft. ( 8 x 4 )Divide 136 by 32 and you’ll get your answer.
7 0
3 years ago
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When evaluating the expression 3 x (3 + 12/3) - 4, Ryan began with 3 + 12. What was Ryan's mistake?
KIM [24]

Answer:

He has to divide 12/3 first

Step-by-step explanation:

it’s like pemdas you have to do that first then you go on to added the 3+ whatever 12/3 is

3 0
3 years ago
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IN one town, the sales tax is 8%. write this percent as a fraction in simplest form.
Natalka [10]
2/25 will be the simplest form
6 0
3 years ago
I need help trying to understand how they solved this equation. Just a little confused.
Misha Larkins [42]

Answer:

0.495

Explanation:

Given the expression:

0.55-1.645\sqrt[]{\frac{0.55(1-0.55)}{220}}

Begin by simplifying the expression under the radical (square root) sign.

\begin{gathered} =0.55-1.645\sqrt[]{\frac{0.55(0.45)}{220}} \\ =0.55-1.645\sqrt[]{\frac{0.2475}{220}} \end{gathered}

Using a calculator, we evaluate the radical:

\begin{gathered} =0.55-1.645\sqrt[]{0.001125} \\ =0.494825 \\ \approx0.495\text{ (to 3 decimal places)} \end{gathered}

3 0
1 year ago
If sin theta = 8/17 and cot theta < 0, what is sec theta?
klasskru [66]

Answer:

-\frac{17}{15}

Step-by-step explanation:

By definition, \cot \theta=\frac{1}{\tan \theta} and \sec \theta=\frac{1}{\cos \theta}. Since since \cot \theta is negative, \tan \theta must also be negative, and since \sin \theta is positive, we must be in Quadrant II.

In a right triangle, the sine of an angle is equal to its opposite side divided by the hypotenuse. The cosine of an angle in a right triangle is equal to its adjacent side divided by the hypotenuse. Therefore, we can draw a right triangle in Quadrant II, where the opposite side to angle theta is 8 and the hypotenuse of the triangle is 17.

To find the remaining leg, use to the Pythagorean Theorem, where a^2+b^2=c^2, where c is the hypotenuse, or longest side, of the right triangle and a and b are the two legs of the right triangle.

Solving, we get:

8^2+b^2=17^2,\\b^2=17^2-8^2,\\b^2=\sqrt{17^2-8^2}=\sqrt{225}=15

Since all values of cosine theta are negative in Quadrant II, all values of secant theta must also be negative in Quadrant II.

Thus, we have:

\sec\theta=\frac{1}{\cos \theta}=-\frac{1}{\frac{15}{17}}=\boxed{-\frac{17}{15}}

6 0
3 years ago
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