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lorasvet [3.4K]
3 years ago
13

Which of the following techniques can be used to separate a homogeneous mixture into its component parts?

Mathematics
2 answers:
bonufazy [111]3 years ago
5 0

Answer:

The answer is

A. Apply pressure

Step-by-step explanation:

Just got it right on my test

Airida [17]3 years ago
4 0

The answer is A. This is because heat, pressure, or differences in density are some methods used to separate homogeneous mixtures.

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the volume of cube A is 216 cubic inches. the length of each edge in cube B is 2 inches longer than the length of each edge in c
Aleonysh [2.5K]
If the side lengths of B are 2x as long as the side lengths of A then the volume of B should be the volume of A^2
216^2=46,656
46,656-216=46,440

This can be more easily displayed with smaller numbers

If cube X were 2*2*2 then the volume would be 8
If cube Y were 4*4*4 then the volume would be 64
8(volume of cube X)^2=64(volume of cube Y)
7 0
3 years ago
Solve for n <br> 3n-2=2n<br> N=
krek1111 [17]

Answer:

Hey there!

3n-2=2n

n-2=0

n=2

Let me know if this helps :)

7 0
3 years ago
Read 2 more answers
Find the perimeter of the rectangle? Needs to be in standard form
vladimir2022 [97]

Answer:

<u>6b - 4a + 22 units</u>

Step-by-step explanation:

Perimeter = 2(length + width)

= 2(3b - 4a + 5 + 6 + 2a)

= 2(3b - 2a + 11)

= <u>6b - 4a + 22 units</u>

4 0
2 years ago
completa con las razones trigonométricas de cada triángulo rectángulo dado y encuentra el lado faltante aplicando el teorema de
Rus_ich [418]

primero vamos a calcular el lado faltante usando el teorema de pitagoras para poder obtener el lado faltante a

a=\sqrt[]{hipotenusa^2-cateto^2}a=\sqrt[]{100^2-85^2}=52.68

a=52.68 m

teniendo el lado faltante podemos calcular las razones trigonometricas

\sin (55)=\frac{85}{100}=0.85\cos (55)=\frac{52.68}{100}=0.52\tan (55)=\frac{85}{52.68}=1.61

\csc (55)=\frac{100}{85}=1.17\sec (55)=\frac{100}{52.68}=1.89\cot (55)=\frac{52.68}{85}=0.61

4 0
1 year ago
Solve for a. r=ab/a+b+c
Marta_Voda [28]

Answer:

r(A + B) = rA + rB,. (4). (r + s)A = rA + sA,. (5) r(sA)=(rs)A;. (6). A(BC)=(AB)C,.

4 0
2 years ago
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