1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mariana [72]
3 years ago
11

At what point in its trajectory does a batted baseball have its minimum speed

Physics
2 answers:
galina1969 [7]3 years ago
8 0

Answer: If air drag can be neglected, how does this compare with the horizontal component of its velocity at other points? Minimum speed occurs at the top, which is the same as the horizontal component of velocity anywhere along the path.

Explanation:

fomenos3 years ago
5 0

Answer: At the highest point in the trajectory the ball will have the minimum speed as the vertical component becomes zero. The horizontal component of the velocity never changes as there is no force acting in horizontal direction.

Explanation:

Hope this helps.

You might be interested in
Connie teaches her children to call adults "sir" and "ma'am" and to say "please" and "thank you." These rituals are known as
Nat2105 [25]
Manners. they are known as manners.
5 0
3 years ago
12. A satellite is put into an orbit at a distance from the center of the Earth equal to twice the distance from the center of t
Kitty [74]

Answer:

Explanation:

F = GmM/d²

As gravity force is proportional to the inverse of the square of the distance,

doubling the distance will reduce the weight to a forth.

F' = GmM/(2d)²

F' = ¼GmM/d²

F' = ¼F = ¼(4000)

F' = 1000 N

6 0
3 years ago
Tidal Forces near a Black Hole. An astronaut inside a spacecraft, which protects her from harmful radiation, is orbiting a black
arlik [135]

Answer:

833.4801043*10^6N on ear that is closer to Black hole.

13.83803929*10^6N On ear that is farther from Black hole.

Explanation:

This problem can be solved as two masses that are at two different location from a bigger mass whose gravity affects both.

tension is an equal and opposite force that is exerted in response to applied force.

so on ear that is closer to black hole would have tension that is equal in magnitude and opposite in direction to gravitational force that ear experience due to the black hole at that location.

this true for ear that is further away from black hole as well.

(1) Force on ear that is closer to black hole.

                                                 F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

                     r = 120km-\frac{6}{100000} km=119.99994km=119999.94m

Note, we have subtracted because ear is closer to black hole.

plugging all this in formula gives.

                                      F = 833.4801043*10^6N

       That is tension of ear.

(2) Force on ear that is further from black hole.

                              F =\frac{m_{1}*m_{2}  }{r^2} G

                    m_{1}= 5*1.989*10^30kg is mass of Black hole.

                     m_{2}= 0.030kg is mass of ear that is close to black hole.

                    G = 6.679*10^-11m^3*kg^-1*s^-2

         this time r is further away from black hole so it would be.

                       r = 120km+\frac{6}{100000} km = 120000.06m

Plugging this all in we get

                          F = 13.83803929N

and that is tension on ear that is further from black hole.

Notice the tension difference, and order of magnitude of tension,it is enormous .

this astronaut is lethally close to black hole.

5 0
3 years ago
during a crash, the acceleration was less than 30g. Calculate the force on a 70 kg person accelerating at this rate.
Igoryamba

Answer:

less than 20580 N

Explanation:

According to the newton's second law of motion

Force = mass * acceleration

(assuming gravitational acceleration =9.8 m/s2 )

acceleration = 30*9.8 = 294 m/s2

acting Force = 70 * 294

                     = 20580 N

Since the acceleration was less than 30g  , acting force should also be less than 20580 N

4 0
3 years ago
A 4 kg bowling ball accelerates 1 m/s2. what is the net force on the ball?
BARSIC [14]

Answer:4N

Explanation:

mass=4kg

Acceleration=1m/s^2

Force=mass x acceleration

Force=4 x 1

Force=4N

4 0
4 years ago
Other questions:
  • Problem 7.036 A long, cylindrical, electrical heating element of diameter D= 10 mm, thermal conductivity k= 240 W/m·K, density r
    12·1 answer
  • If the period of a pendulum is 4.0 <br> s, what is it's fequency?
    13·1 answer
  • Running on a treadmill is slightly easier than running outside because there is no drag force to work against. suppose a 60 kg r
    8·1 answer
  • 6)the speed of light is approximately​ 186,000 mi/sec. It takes light from a particular star approximately 9 yrs to reach Earth.
    11·1 answer
  • Give 2 ways to increase the temperature of gas ​
    14·1 answer
  • What do the Tropopause, Stratopause, and Mesopause all have in common? Each is a
    13·2 answers
  • PLEASE HELP MEEE You can make a smoothie in a blender with a power of 400 watts and an efficiency of 85 percent. How much energy
    14·1 answer
  • Jenny is doing her homework when Jenny writes, the pencil exerts a force of 5N on the paper. The area of the pencil in contact w
    8·2 answers
  • Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of
    12·1 answer
  • Label The Motion Graph.<br> Please it’s due today. Thank You xx
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!