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Over [174]
3 years ago
11

6)the speed of light is approximately​ 186,000 mi/sec. It takes light from a particular star approximately 9 yrs to reach Earth.

How many miles away is the star from​ Earth? Express the answer in scientific notation. Use 365 days in 1 year. The star is nothing miles away from Earth.
Physics
1 answer:
NeTakaya3 years ago
5 0

Answer:

5.2791264*10¹³

Explanation:

Convert the 9 years to seconds and then multiple it by 186000

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please help me with my question I will like and mark as brainliest NO LINKS THEY DON'T WORK AND IF U DON'T KNOW THE ANSWER PLS D
bearhunter [10]

Answer:

a)

Weight in Air = 0.3N

Weight in Water = 0.25N

Weight in Liquid = 0.24N.

Upthrust /Buoyant Force = Weight in Air – Weight in Fluid(Water in this case)

= 0.3 – 0.25

= 0.5N.

b) R.D of Body = Density of Body/Density of Standard Fluid(Water).

There's a Derived Formula for RD.

I'm gonna Apply it here.

Ask me for the derivation in the Comment section if you need it.

RD = α/ρ = (Weight in Air) / (Upthrust Force)

Where

α = density of the Body(or reference substance)

ρ = density of standard fluid (water)

= 0.3/0.05 = 6.

c) RD of Liquid = (Density of Liquid) /(Density of standard Fluid(water)

Or we just go by that formula

RD of Liquid = Weight in Air/Upthrust(In Liquid)

We'll be using the Upthrust in that Liquid now.

= 0.3 – 0.24 = 0.06

RD = 0.3/0.06 = 5.

7 0
2 years ago
What is the fastest the block can be spun at without breaking with the block weighing 10kg and spinning horizontally with a 2m s
larisa86 [58]

The fastest speed before the string breaks is 9.5 m/s

Explanation:

The motion of the block is a uniform circular motion, which is a circular motion with constant speed. The force that keeps the block in circular motion is called centripetal force; its direction is towards the centre of the circle and its magnitude is given by:

F=m\frac{v^2}{r}

where

m is the mass of the block

v is its speed

r is the radius of the circle

In this problem, the centripetal force is provided by the tension in the string, T, so we can write:

T=m\frac{v^2}{r}

The string breaks when the centripetal force becomes larger than the maximum tension in the string:

T_{max}

Re-arranging the equation  for v,

v>\sqrt{\frac{Tr}{m}}

and here we have:

T = 450 N

m = 10 kg

r = 2 m

Substituting,

v>\sqrt{\frac{(450)(2)}{10}}=9.5 m/s

So, the fastest speed before the string breaks is 9.5 m/s.

Learn more about circular motion:

brainly.com/question/2562955

brainly.com/question/6372960

#LearnwithBrainly

7 0
3 years ago
The Atomic Mass of an element is
dedylja [7]

Answer:

C) A ratio based on the mass of a carbon-12 atom

Explanation:

For each element, there is a characteristic number of protons, this number represent a type of atom and its called the atomic number

On the other hand we have the number of neutrons, and for one element which difers only on the number of neutrons, we have different isotopes from one element.

Together, protons and neutrons define the mass number

One property linked with the mass number, is the atomic mass, which is formerly expressed as "uma" (atomic mass unit)

By definition, one atom of carbon-12 (with 6 neutrons) has an atomic mass of 12 umas

6 0
4 years ago
Read 2 more answers
The Moon (7.35 x 10^22 kg) is 3.85 x 10^8 m from the Earth and orbits around it in a circle. a) If the period of the Moon is 27.
Lemur [1.5K]

a) Speed of the Moon: 1025 m/s

The speed of the moon is equal to the ratio between the circumference of its orbit and the orbital period:

v=\frac{2 \pi r}{T}

where

r=3.85\cdot 10^8 m is the radius of the orbit of the Moon

T=27.3 d \cdot (24 h/d) \cdot (60 min/h) \cdot (60 s/min)=2.36\cdot 10^6 s is the orbital period

Substituting into the formula, we find

v=\frac{2 \pi (3.85\cdot 10^8 m)}{2.36\cdot 10^6 s)}=1025 m/s


b) Centripetal force: 2.0 \cdot 10^{20} N

The centripetal force acting on the Moon is given by:

F=m\frac{v^2}{r}

where

m=7.35 \cdot 10^{22}kg is the mass of the Moon

v=1025 m/s is its orbital speed

r=3.85\cdot 10^8 m is the radius of the orbit

Substituting into the formula, we find

F=(7.35 \cdot 10^{22} kg) \frac{(1025 m/s)^2}{3.85\cdot 10^8 m}=2.0 \cdot 10^{20} N


c) Gravitational force

The only relevant force that acts on the Moon, and that keeps the Moon in circular motion around the Earth, is the gravitational force exerted by the Earth on the Moon. In fact, this force "pulls" the Moon towards the Earth, so towards the centre of the orbit of the Moon, therefore it acts as source of centripetal force for the Moon.

8 0
3 years ago
The cruise ship Oasis of the Seas has a gross weight of approximately 220,000,000 pounds. Although pure water has a density of 6
lys-0071 [83]

By carefully reading the question, we are able to discern from its wording the fact that Oasis of the Seas is not a submarine. Instead, wherever she sails, she is expected to <em>float</em> on the surface of the briny deep.

A floating object displaces water equal to its own weight.

So the Oasis must displace

(approx 220,000,000 lbs)/(65 lbs/ft³) =

approx <em>3,384,615 ft³</em> of sea water

6 0
3 years ago
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