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Digiron [165]
3 years ago
12

Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of

planet B. Which statement correctly explains the weight you would experience on each planet? A. You would weigh less on planet B because it is traveling twice as fast as planet A. B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same. O C. You would weigh more on planet B because it is traveling twice as fast as planet A. D. You would weigh the same on both planets because your mass would adjust depending on the planet's speed.​
Physics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are m_A and m_B respectively.

As masses are equal, so m_A=m_B\cdots(i).

Similarly, let the radii of the planets A and B are r_A and r_B respectively.

As radii are equal, so r_A=r_B\cdots(ii).

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, w_A= \frac {Gm_Am}{r_A^2}

my weight of planet B, w_B=\frac {Gm_Bm}{r_B^2}

By using equations (i) and (ii),

w_B=\frac {Gm_Am}{r_A^2}=w_A.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (B) is correct.

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Determine the ratio of the resistivity of pure water to silver?
shutvik [7]
Silver is a very good conductor, this means its resistivity is very low (from table, we can check the precise value, which is \rho_s = 1.6 \cdot 10^{-8} \Omega m).

Pure water, instead, is a very bad conductor, this means its resistivity is very high, of order of k \Omega \cdot m (10^3 \Omega m ). Even without knowing the precise value of the pure water resistivity, we can estimate the ratio between the pure water resistivity and the silver resistivity by comparing the two orders of magnitude:
r= \frac{10^3 \Omega m}{10^{-8} \Omega m}  \sim 10^{11}

Therefore, we can say that the correct answer is
3 \cdot 10^{11} : 1
3 0
3 years ago
The world record for the 100.0 meter dash is 9.580 seconds. Find the speed of the runner in miles per hour.
grigory [225]

Answer:

233.1 miles per hours

Explanation:

Speed: This is defined as the ratio of distance to time. The S.I unit of speed is m/s. speed is a vector quantity because it can only be represented by magnitude only. Mathematically, speed can be expressed as,

S = d/t ....................... Equation 1

Where S = speed of the runner, d = distance covered, t = time.

Given: d = 100 meter , t = 9.580 seconds

Conversion:

If, 1 meter =  0.00062 miles

Then, 100 meters = (0.00062×100) miles = 0.62 miles.

Also

If, 3600 s = 1 h

Then, 9.580 s = (1×9.580)/3600 = 0.00266 hours.

Substitute into equation 1

S = 0.62/0.00266

S = 233.1 miles per hours.

Hence the runner speed is 233.1 miles per hours

7 0
3 years ago
Is sunlight and beat abiotic or biotic?
n200080 [17]
The sun is abiotic-Brainly.com
8 0
3 years ago
Ted is a high school student. He is very good at math, but he is not a very good English student. He likes all of his teachers;
scoray [572]
I think the correct answer is

D) Ted associated being asked a question with embarrassment.

Glad I could help, and good luck!

AnonymousGiantsFan
3 0
4 years ago
Read 2 more answers
A 4 kg bowling bowl is sitting on a table 1 meter off the ground. How much potential energy does it have?
il63 [147K]

Answer:

\huge\boxed{\sf P.E. = 39.2\ Joules}

Explanation:

<u>Given Data:</u>

Mass = m = 4 kg

Acceleration due to gravity = g = 9.8 m/s²

Height = h = 1 m

<u>Required:</u>

Potential Energy = P.E. = ?

<u>Formula:</u>

P.E. = mgh

<u>Solution:</u>

P.E. = (4)(9.8)(1)

P.E. = 39.2 Joules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
5 0
3 years ago
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