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Digiron [165]
2 years ago
12

Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of

planet B. Which statement correctly explains the weight you would experience on each planet? A. You would weigh less on planet B because it is traveling twice as fast as planet A. B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same. O C. You would weigh more on planet B because it is traveling twice as fast as planet A. D. You would weigh the same on both planets because your mass would adjust depending on the planet's speed.​
Physics
1 answer:
Ganezh [65]2 years ago
4 0

Answer:

B. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are m_A and m_B respectively.

As masses are equal, so m_A=m_B\cdots(i).

Similarly, let the radii of the planets A and B are r_A and r_B respectively.

As radii are equal, so r_A=r_B\cdots(ii).

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A, w_A= \frac {Gm_Am}{r_A^2}

my weight of planet B, w_B=\frac {Gm_Bm}{r_B^2}

By using equations (i) and (ii),

w_B=\frac {Gm_Am}{r_A^2}=w_A.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (B) is correct.

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I believe it goes as the following::

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An object is in circular motion. How will the object behave if the centripetal force is removed
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The object will sail away in a straight line ... continuing in the same direction it was going when the centripetal force stopped.

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Two people carry a heavy electric motor by placing it on a light board 2.45 m long. One person lifts at one end with a force of
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Answer:

W=1055N

Explanation:

In order to solve this problem, we must first do a drawing of the situation so we can visualize theh problem better. (See attached picture)

In this problem, we will ignore the board's weight. As we can see in the free body diagram of the board, there are only three forces acting on the system and we can say the system is in vertical equilibrium, so from this we can say that:

\sum F=0

so we can do the sum now:

F_{1}+F_{2}-W=0

when solving for the Weight W, we get:

W=F_{1}+F_{2}

and now we can substitute the given data, so we get:

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5 0
3 years ago
Part A Determine the absolute pressure on the bottom of a swimming pool 30.0 m by 8.7 m whose uniform depth is 1.8 m . Express y
Sphinxa [80]

Answer:

17.66 kPa

Explanation:

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V = 30 * 8.7 * 1.8 = 469.8 cubic meters

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W = mg = \rho V g = 1000 * 469.8 * 9.81 = 4608738 N

The area of the bottom

A = 30 * 8.7 = 261 square meters

Therefore the pressure is its force over unit area

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The answer is Hertz (Hz) named in honor of the German scientist Heinrich Hertz, who first conclusively proved the existence of electromagnetic waves.
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