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stepladder [879]
2 years ago
13

WILL GIVE BRAINLIEST! what are the values of a and b so the system of equations has infinitely many solutions?

Mathematics
1 answer:
larisa86 [58]2 years ago
3 0

Answer:

a = 6

b = 3/4

Step-by-step explanation:

They both need to have the same slope.

The slope in the first equation is 6

That means that the second equation must have a = 6

They both need to have the same y intercept

The second equation has a y intercept of 3/4

Therefore b in the first equation, must be 3/4

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pentagon [3]

Answer:

= x 3048

Step-by-step explanation:

6 0
2 years ago
Find slope and y-intercept<br> 5x+3y=-6
katen-ka-za [31]

Answer:

m=-\frac53; q=-2

Step-by-step explanation:

Let's bring the line in the classical y=mx+q form

3y= -5x-6\\y=-\frac53 x -2

At this point we have the two values -\frac53 for the slope and 2 for the intercept

6 0
3 years ago
A triangle has an area of 56 square units. It's night is 14 units. What is the length of its base?
NNADVOKAT [17]

Answer:

8 units

Step-by-step explanation:

b(14)/2 = 56

14b = 112

b = 8 units

4 0
3 years ago
I need some help with math
Valentin [98]

Answer:

PT, VP

Step-by-step explanation:

if p is the center and T V and W are on the circle

the radius goes from the center of the circle to the edge of the circle

then PW PT and PW are radii of the circle


6 0
3 years ago
Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at
kari74 [83]

Answer: 5 km walking and 30 km by bus

Step-by-step explanation:

Yochanan walked from home to the bus stop at an average speed of 5 km / h. He immediately got on his school bus and traveled at an average speed of 60 km / h until he got to school. The total distance from his home to school is 35 km, and the entire trip took 1.5 hours. How many km did Yochanan cover by walking and how many did he cover by travelling on the bus?

walking - 5km/h                                         bus - 60km/h

distance walking - d₁                                 distance bus - d₂

time walking - t₁                                         time bus - t₂

d₁ + d₂ = 35

t₁ + t₂ = 1.5

v = d/t

vwalking = d₁/t₁

5 = d₁/t₁ ⇒ d₁ = 5t₁

vbus = d₂/t₂

60 = d₂/t₂ ⇒ d₂ = 60t₂

d₁ + d₂ = 35 ⇒ 5t₁ + 60t₂ = 35

_________________________

5t₁ + 60t₂ = 35

t₁ + t₂ = 1.5  (*-5)

5t₁ + 60t₂ = 35

-5t₁ -5t₂ = -7.5   (+)

__________________________

55t₂ = 27.5

t₂ = 27.5/55 = 0.5 h

t₁ + t₂ = 1.5 ⇒ t₁ = 1.5 - 0.5 = 1h

d₁ = 5t₁ ⇒ d₁ = 5.1 = 5 km

d₂ = 60t₂ ⇒ d₂ = 30.0.5 = 30 km

6 0
3 years ago
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