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notsponge [240]
3 years ago
11

If possible may someone help me please?

Mathematics
1 answer:
Orlov [11]3 years ago
4 0

Answer:

Given, ∠MNP=107 degree.

Therefore, ∠QPN= 107 degree. [as, MN=PQ]

We know, sum of four angles of a quadrilateral is 360 degree.

And as MN=PQ, ∠NMQ=∠MQP.

Therefore, ∠MQP= {360 degree-( 107degree+ 107 degree)}/2

                             =( 360 degree-214 degree)/2

                            = 146 degree/2

                            =73 degree.

hope this will help you.

                           

Step-by-step explanation:

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telo118 [61]

Answer:

The required equation for the amount of Simple Internet = \frac{450,000 \times 1 \times 3.5}{100}

Step-by-step explanation:

Here , Principal amount = $450,000

Time  = 1 year

Rate of Interest = 3.5%

Now,SIMPLE INTEREST  = \frac{P \times R \times T}{100}

So, here SI  = \frac{450,000 \times 1 \times 3.5}{100}

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7 0
4 years ago
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Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

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