ACIDIC BEHAVIOR OF SOLUTION
Answer:
P = 164 Atm
Explanation:
PV = nRT => P = nRT/V
n = 10.0 moles
R = 0.08206 L·Atm/mol·K
T = 27.0°C = 300 K
V = 1.50 Liters
P = (10.0 mol)(0.08206 L·Atm/mol·K )(300 K)/(1.50 Liters) = 164.12 Atm ≅ 164 Atm (3 sig. figs.)
Answer:
hope this help by the way found off of yahoo
Explanation:
Calculate the number of grams of nitrogen dioxide that are produced from
4 moles of nitric oxide.
2NO(g) + O2(g) -->2NO2(g)
I really need help with this... I need to know how to work it too... I can balance it out but not sure about grams... This is it balanced out with 4 moles of nitric oxide
4NO(g) + 2O2(g) ->4NO2(g) please help and explain i want to learn this