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2 years ago

Helga has a box. She wants to determine how much the box can hold. Which measurement should she calculate?

Chemistry

2 answers:

zaharov [31]2 years ago

3 0

C) volume

Explanation:

hope it helps !

Misha Larkins [42]2 years ago

3 0

Answer:

Volume. "How much the box can hold" means how much matter can fit into the box

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A cylindrical piece of metal is 4.5 dm in height with radius of 5.50 x 10^-5 km.

adell [148]

Answer:

a) $V=4.3x10^3mL$

b) $V=4.3x10^6mm^3$

c) $\rho=1.5x10^5g/L$

Explanation:

Hello,

a) In this case, the given height in cm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{100cm}{1m}=45cm$

And the radius in cm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{100cm}{1m}=5.5cm$

Thus, the volume in cubic centimeters which is also equal in mL (1cm³=mL) is:

$V=\pi (5.5cm)^2*45cm\\\\V=4.3x10^3cm^3=4.3x10^3mL$

b) In this case, the given height in mm is:

$h=4.5dm*\frac{1m}{10dm}* \frac{1000mm}{1m}=450mm$

And the radius in mm is:

$r=5.50x10^{-5}km*\frac{1000m}{1km}*\frac{1000mm}{1m}=55mm$

Thus, the volume in cubic millimeters is:

$V=\pi (55mm)^2*450mm\\\\V=4.3x10^6mm^3$

c) Finally, since 1000 mL equal 1 L, the required density in g/L turns out:

$\rho=\frac{m}{V}=\frac{6.54x10^5g}{4.3x10^3mL}*\frac{1000mL}{1L}\\ \\\rho=1.5x10^5g/L$

Best regards.

8 0

3 years ago

If 8.00 mol of an ideal gas at stp were confined to a cube, what would be the length in cm of an edge of this cube?

MatroZZZ [7]

To solve this problem it is fundamentally, just look for the volume of the gas and convert it to cm3. At STP 1 mole = 22.4 liters. 8.00 moles x 22.4 liters/mole = 179.2 liters = 179,200 cm^3 Then. get the cube root of 179,200 cm^3. This would be equal to 56.38 cm and thus would be the length of the edge of this cube.

6 0

3 years ago

How many doubtful digit(s) is/are allowed in any measured quantity?

Mnenie [13.5K]

Answer:

zero

Explanation:

I I think one should be so accurate with measurements and experiments

3 0

2 years ago

How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.

SVETLANKA909090 [29]

Answer:

umm idk if I was right or not

7 0

3 years ago

Iron reacts slowly with oxygen and water to form a compound commonly called rust (Fe₂O₃?4H₂O). For 45.2 kg of rust, calculate

Mashcka [7]

Rust (Fe2O3. 4H2O) is formed when iron interacts slowly with oxygen and water. Mass of Fe in grams is 2.18 x 10⁴ g.

<h3>What is the explanation?</h3>

There are 2 moles of Fe atoms in 1 mole of Fe2O3-4H2O. The number of moles of Fe atoms in 45.2 kg rust is shown below.

Moles of Fe = 195.01 mol Fe₂O₃.4H₂O ( $\frac{2 mol Fe }{1 mol Fe₂O₃.4H₂O}$ )

Moles of Fe = 390.02 mol Fe

Multiply the calculated number of moles of iron, Fe, by its molar mass which is 55.85 $\frac{g}{mol}$

Mass of Fe = 390.02 mol Fe ( $\frac{55.85 g Fe}{mol Fe}$ )

Mass of Fe = 2.18 x 10⁴ g Fe

Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grams per mole of a substance, to put it another way.

To learn more about moles visit:

brainly.com/question/26416088

#SPJ4

4 0

1 year ago