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seropon [69]
3 years ago
13

You want to save $5000 to buy a car. You have $1325 in your account right now. You plan to work and save $150 out of each payche

ck each week for the car. How many weeks will it take you to reach your goal?
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
3 0

Answer:

approximately 25 weeks

Step-by-step explanation:

take $ 5000-$ 1325=$3675 this is what is remaining to achieve $5000

if you get $150 in one week what about $3675 is equal to how many weeks

$150=1 week

$3675=??weeks

<u>$</u><u>3675</u><u> </u><u>×</u><u> </u><u>1 week</u>

<u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u> </u><u>$</u><u>150</u>

<u> </u><u> </u><u> </u>

<u>Ans</u><u> </u><u>=</u><u>24</u><u>.</u><u>5</u><u> </u><u>the</u><u> </u><u>same</u><u> </u><u>as</u><u> </u><u>25</u><u> </u><u>weeks</u>

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Alisiya [41]

Answer:

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Step-by-step explanation:

(x,y) is a pair of real numbers. The meaning is: (x,y) is an ordered pair of numbers belonging to R×R=R2 .

6 0
3 years ago
For many years businesses have struggled with the rising cost of health care. But recently, the increases have slowed due to les
kaheart [24]

Answer:

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

Step-by-step explanation:

Data given and notation  

n=1000 represent the random sample taken    

\hat p=0.52 estimated proportion of of U.S. employers were likely to require higher employee contributions for health care coverage

\alpha=0.05 represent the significance level (no given, but is assumed)    

Solution to the problem

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=1.96

The margin of error for this case is given by:

ME= z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

And replacing we got:

ME = 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.0259

And replacing into the confidence interval formula we got:

0.52 - 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.4941

0.52 + 1.64*\sqrt{\frac{0.52(1-0.52)}{1000}}=0.5459

And the 95% confidence interval would be given (0.4941;0.5459).

5 0
3 years ago
Four points are always coplanar if: Check all that apply. A. all of them are collinear B. they are not in the same plane. C. thr
pentagon [3]

They are collinear

they lie in the same plane

7 0
3 years ago
find the height of the cylinder below whose volume is approximately 1000 cubic inches use 3.14 for pi round your answer to the n
gtnhenbr [62]

Answer:

h = 1000 / (3.14)(r²)

Step-by-step explanation:

Given in the question,

volume of cylinder = 1000 inches³

Formula to use

V = πr²h

where V = volume

           π = 3.14

           r = radius

           h = height

1000 = (3.14)(r²)(h)

h = 1000 / (3.14)(r²)

               

5 0
3 years ago
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