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emmainna [20.7K]
2 years ago
11

Help with number one only,no bad answers or links please.

Mathematics
2 answers:
Scrat [10]2 years ago
8 0

Answer: 180 ft^3

Step-by-step explanation:

bonufazy [111]2 years ago
8 0

Answer: 180 ft is the answer

Step-by-step explanation:

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162*0.967=what? {this is multiplication}
Veronika [31]

Answer:

156.654

Step-by-step explanation:

162*.967=156.654

6 0
2 years ago
What is the shaded portion of the circle
blagie [28]

Answer:

(5\pi-11.6)\ ft^{2}

Step-by-step explanation:

we know that

The area of the shaded region is equal to the area of the sector minus the area of the triangle

step 1

Find the area of the circle

the area of the circle is equal to

A=\pi r^{2}

we have

r=5\ ft

substitute

A=\pi (5)^{2}

A=25\pi\ ft^{2}

step 2

Find the area of the sector

we know that

The area of the circle subtends a central angle of 360 degrees

so

by proportion find out the area of a sector by a central angle of 72 degrees

\frac{25\pi}{360}=\frac{x}{72}\\ \\x=72*25\pi /360\\ \\x=5\pi\ ft^{2}

step 3

Find the area of triangle

The area of the triangle is equal to

A=\frac{1}{2}(2.9+2.9)(4)= 11.6\ ft^{2}

step 4

Find the area of the shaded region

Subtract the area of the triangle from the area of the sector

(5\pi-11.6)\ ft^{2}

8 0
2 years ago
50 PTS!!!
nydimaria [60]

Answer:

the data of the cubic

as it the distance between the two integers closed under addition

5 0
2 years ago
Don't get this
kap26 [50]
I'll talk you through it so you can see why it's true, and then
you can set up the 2-column proof on your own:

Look at the two pointy triangles, hanging down like moth-wings
on each side of 'OC'.

-- Their long sides are equal,  OA = OB, because both of those lines
are radii of the big circle.

-- Their short sides are equal, OC = OC, because they're both the same line.

-- The angle between their long side and short side ... the two angles up at 'O',
are equal, because OC is the bisector of the whole angle there.

-- So now you have what I think you call 'SAS' ... two sides and the included angle of one triangle equal to two sides and the included angle of another triangle.
(When I was in high school geometry, this was not called 'SAS' ... the alphabet
did not extend as far as 'S' yet, and we had to call this congruence theorem
"broken arrow".)

These triangles are not congruent the way they are now, because one is
the mirror image of the other one.  But if you folded the paper along 'OC',
or if you cut one triangle out and turn it over, it would exactly lie on top of
the other one, and they would be congruent.

So their angles at 'A' and at 'B' are also equal ... those are the angles that
you need to prove equal.
5 0
3 years ago
Find the measure of the indicated angle. Round to the nearest degree.
yuradex [85]
Angle=28.1416
Rounded=28


hope this helps




pls give brainliest!
8 0
2 years ago
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